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The is a powerful tool for converting functions from the s-domain back to the . It's crucial for analyzing system behavior after performing operations in the s-domain, like working with transfer functions or .

and are key techniques for finding inverse transforms. These methods allow us to break down complex s-domain functions into simpler terms, making it easier to convert back to the time domain and understand system responses.

Inverse Laplace Transform

Inverse Laplace transform definition

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  • Converts a function from the s-domain () back to the time domain (t-domain)
  • Denoted as L1{F(s)}=f(t)\mathcal{L}^{-1}\{F(s)\} = f(t), where F(s)F(s) is the Laplace transform of the time-domain function f(t)f(t)
  • Recovers the original time-domain function from its Laplace transform representation
  • Essential for analyzing the behavior of systems in the time domain after performing operations in the s-domain (transfer functions, convolution)

Partial fraction expansion for inversion

  • Decomposes rational Laplace transforms into a sum of simpler terms
  • is a ratio of two polynomials in the s-domain, F(s)=P(s)Q(s)F(s) = \frac{P(s)}{Q(s)}
  • Factors the denominator polynomial Q(s)Q(s) and expresses the rational function as a sum of partial fractions
    • Each partial fraction has a denominator that is a linear or quadratic factor of Q(s)Q(s) (, )
  • Resulting partial fractions are easier to inverse Laplace transform individually using Laplace transform pairs or tables
  • Time-domain function f(t)f(t) is obtained by summing the inverse Laplace transforms of each partial fraction term

Laplace transform pairs and tables

  • Set of correspondences between time-domain functions and their respective Laplace transforms
  • Derived from the properties of the Laplace transform and well-established for common functions (exponential, sinusoidal)
  • Compilation of these pairs used as a reference for finding the inverse Laplace transform of a given function
    • Tables list the time-domain function f(t)f(t) and its corresponding Laplace transform F(s)F(s)
  • Locate the entry in the table that matches the given Laplace transform and read off the corresponding time-domain function
  • Common Laplace transform pairs:
    • L{1}=1s\mathcal{L}\{1\} = \frac{1}{s}
    • L{tn}=n!sn+1\mathcal{L}\{t^n\} = \frac{n!}{s^{n+1}}, where nn is a non-negative integer
    • L{eat}=1sa\mathcal{L}\{e^{at}\} = \frac{1}{s-a}
    • L{sin(at)}=as2+a2\mathcal{L}\{\sin(at)\} = \frac{a}{s^2+a^2}
    • L{cos(at)}=ss2+a2\mathcal{L}\{\cos(at)\} = \frac{s}{s^2+a^2}

System Response in Time Domain

Time-domain response from Laplace transforms

  • Determined by finding the inverse Laplace transform of the system's
  • Transfer function H(s)H(s) is the ratio of the Laplace transform of the output Y(s)Y(s) to the Laplace transform of the input X(s)X(s), H(s)=Y(s)X(s)H(s) = \frac{Y(s)}{X(s)}
  • Given H(s)H(s) and X(s)X(s), the Laplace transform of the output is calculated as Y(s)=H(s)X(s)Y(s) = H(s) \cdot X(s)
  • To find the time-domain output y(t)y(t):
    1. Take the inverse Laplace transform of Y(s)Y(s) using partial fraction expansion (if necessary)
    2. Use Laplace transform pairs or tables
    • y(t)=L1{Y(s)}=L1{H(s)X(s)}y(t) = \mathcal{L}^{-1}\{Y(s)\} = \mathcal{L}^{-1}\{H(s) \cdot X(s)\}
  • Resulting time-domain function y(t)y(t) represents the system's response to the given input in the time domain (step response, impulse response)
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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