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1.4 Inverse Functions

3 min readjune 24, 2024

Inverse functions flip the roles of input and output, allowing us to "undo" a function's effect. They're crucial for solving equations and understanding relationships between variables. We use tools like the to check if a function is invertible.

help us find angles from ratios, with specific domains and ranges. When we combine a function with its inverse, we get the identity function. This relationship is key in calculus, especially when dealing with derivatives and solving complex equations.

Inverse Functions

Horizontal line test for invertibility

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  • Determines if a function is one-to-one meaning each x-value corresponds to exactly one y-value and vice versa
    • Functions that are not one-to-one fail the because some x-values map to multiple y-values (parabola)
  • Involves drawing horizontal lines across the graph of the function
    • If any horizontal line intersects the graph more than once, the function is not invertible ()
    • If no horizontal line intersects the graph more than once, the function is invertible ()
  • A function that passes the horizontal line test is injective

Computation and graphing of inverses

  • Steps to find the inverse of a function f(x)f(x):
    1. Replace f(x)f(x) with yy
    2. Interchange xx and yy variables
    3. Solve the resulting equation for yy
    4. Replace yy with f1(x)f^{-1}(x) to denote the
  • The of f1f^{-1} is the of ff and the range of f1f^{-1} is the of ff
    • For example, if f(x)=x2f(x) = x^2 with domain [0,)[0, \infty), then f1(x)=xf^{-1}(x) = \sqrt{x} with domain [0,)[0, \infty)
  • Graphing inverse functions involves reflecting the graph of ff across the line y=xy = x
    • If (2,4)(2, 4) is a point on the graph of ff, then (4,2)(4, 2) is a point on the graph of f1f^{-1}

Applications of inverse trigonometric functions

  • allow you to find the angle given a trigonometric ratio
    • sin1(x)\sin^{-1}(x) or arcsin(x)\arcsin(x) outputs the angle whose sine is xx
    • cos1(x)\cos^{-1}(x) or arccos(x)\arccos(x) outputs the angle whose cosine is xx
    • tan1(x)\tan^{-1}(x) or arctan(x)\arctan(x) outputs the angle whose tangent is xx
  • The domain of inverse trigonometric functions is limited to the range of their corresponding trigonometric function
    • sin1(x)\sin^{-1}(x) has domain [1,1][-1, 1] and range [π2,π2][-\frac{\pi}{2}, \frac{\pi}{2}] (first and fourth quadrants)
    • cos1(x)\cos^{-1}(x) has domain [1,1][-1, 1] and range [0,π][0, \pi] (first and second quadrants)
    • tan1(x)\tan^{-1}(x) has domain (,)(-\infty, \infty) and range (π2,π2)(-\frac{\pi}{2}, \frac{\pi}{2}) (first and fourth quadrants)
  • Example calculation: If cos(θ)=32\cos(\theta) = -\frac{\sqrt{3}}{2} and θ\theta is in the third quadrant, then θ=cos1(32)+π\theta = \cos^{-1}(-\frac{\sqrt{3}}{2}) + \pi

Functions vs their inverses

  • Composing a function with its inverse results in the identity function
    • (ff1)(x)=x(f \circ f^{-1})(x) = x for all xx in the domain of f1f^{-1} (plugging in f1(x)f^{-1}(x) into f(x)f(x) returns xx)
    • (f1f)(x)=x(f^{-1} \circ f)(x) = x for all xx in the domain of ff (plugging in f(x)f(x) into f1(x)f^{-1}(x) returns xx)
  • The derivative of an is related to the derivative of the original function
    • If ff is differentiable and invertible, then f1f^{-1} is also differentiable
    • (f1)(x)=1f(f1(x))(f^{-1})'(x) = \frac{1}{f'(f^{-1}(x))} (reciprocal of the derivative of ff evaluated at f1(x)f^{-1}(x))

Equations with inverse functions

  • Inverse functions can be used to solve equations of the form f(x)=af(x) = a
    1. Apply f1f^{-1} to both sides of the equation: f1(f(x))=f1(a)f^{-1}(f(x)) = f^{-1}(a)
    2. Simplify the left side using the property (f1f)(x)=x(f^{-1} \circ f)(x) = x: x=f1(a)x = f^{-1}(a)
  • Inverse trigonometric functions can be used to solve trigonometric equations
    • To solve cos(x)=22\cos(x) = -\frac{\sqrt{2}}{2}, apply cos1\cos^{-1} to both sides:
      1. cos1(cos(x))=cos1(22)\cos^{-1}(\cos(x)) = \cos^{-1}(-\frac{\sqrt{2}}{2})
      2. x=cos1(22)+2πnx = \cos^{-1}(-\frac{\sqrt{2}}{2}) + 2\pi n or x=cos1(22)+2πnx = -\cos^{-1}(-\frac{\sqrt{2}}{2}) + 2\pi n, where nn is an integer

Function properties and invertibility

  • A function is surjective if every element in the codomain is mapped to by at least one element in the domain
  • A monotonic function is either entirely increasing or entirely decreasing, making it invertible
  • (f ∘ g) can be used to create new functions, which may or may not be invertible depending on the properties of f and g
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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