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2.3 The Dot Product

4 min readjune 24, 2024

Vector operations are crucial in understanding 3D space. They help us calculate distances, angles, and relationships between objects. Dot products, projections, and are key tools for analyzing vector interactions.

These concepts have wide-ranging applications in physics and engineering. From calculating by forces to determining perpendicularity, vector operations provide a powerful framework for solving real-world problems in three dimensions.

Vector Operations and Applications

Dot product calculation and interpretation

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  • Calculates the of two vectors a=a1,a2,a3\vec{a} = \langle a_1, a_2, a_3 \rangle and b=b1,b2,b3\vec{b} = \langle b_1, b_2, b_3 \rangle by multiplying corresponding components and summing the results: ab=a1b1+a2b2+a3b3\vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3
  • Geometrically interprets the dot product as the product of the vector magnitudes and the cosine of the angle between them: ab=abcosθ\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta, where θ\theta is the angle between a\vec{a} and b\vec{b}
    • Example: If a=1,2,3\vec{a} = \langle 1, 2, 3 \rangle and b=4,5,6\vec{b} = \langle 4, 5, 6 \rangle, then ab=1(4)+2(5)+3(6)=32\vec{a} \cdot \vec{b} = 1(4) + 2(5) + 3(6) = 32
  • Results in a scalar value, not a vector, representing the degree to which the vectors are aligned
    • Positive dot product indicates vectors pointing in similar directions (acute angle)
    • Negative dot product indicates vectors pointing in opposite directions (obtuse angle)
  • Also known as the in linear algebra and functional analysis

Vector perpendicularity via dot product

  • Determines if two vectors are perpendicular (orthogonal) by checking if their dot product is zero: ab=0\vec{a} \cdot \vec{b} = 0 if and only if ab\vec{a} \perp \vec{b}
    • Example: a=1,0,0\vec{a} = \langle 1, 0, 0 \rangle and b=0,1,0\vec{b} = \langle 0, 1, 0 \rangle are perpendicular since ab=1(0)+0(1)+0(0)=0\vec{a} \cdot \vec{b} = 1(0) + 0(1) + 0(0) = 0
  • Follows from the of the dot product: if ab\vec{a} \perp \vec{b}, then cosθ=0\cos\theta = 0 (since θ=90\theta = 90^\circ), and thus ab=0\vec{a} \cdot \vec{b} = 0
    • Useful for finding orthogonal vectors or verifying perpendicularity in 3D space

Direction cosines and significance

  • Computes the direction cosines of a vector a=a1,a2,a3\vec{a} = \langle a_1, a_2, a_3 \rangle as the cosines of the angles between the vector and the positive x, y, and z axes: cosα=a1a\cos\alpha = \frac{a_1}{|\vec{a}|}, cosβ=a2a\cos\beta = \frac{a_2}{|\vec{a}|}, and cosγ=a3a\cos\gamma = \frac{a_3}{|\vec{a}|}
    • Example: For a=1,2,2\vec{a} = \langle 1, 2, 2 \rangle, a=12+22+22=3|\vec{a}| = \sqrt{1^2 + 2^2 + 2^2} = 3, so cosα=13\cos\alpha = \frac{1}{3}, cosβ=23\cos\beta = \frac{2}{3}, and cosγ=23\cos\gamma = \frac{2}{3}
  • Describes the orientation of a vector in 3D space relative to the coordinate axes
  • Satisfies the property that the sum of the squares of the direction cosines is always 1: cos2α+cos2β+cos2γ=1\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1
    • Helps normalize vectors and ensures consistency in vector orientation representation

Vector projections explained

  • Calculates the of a vector a\vec{a} onto a vector b\vec{b} as the component of a\vec{a} that is parallel to b\vec{b}: projba=abbbb=abb2b\text{proj}_{\vec{b}}\vec{a} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|}\frac{\vec{b}}{|\vec{b}|} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^2}\vec{b}
    • Example: If a=1,2,3\vec{a} = \langle 1, 2, 3 \rangle and b=1,0,0\vec{b} = \langle 1, 0, 0 \rangle, then projba=1(1)+2(0)+3(0)12+02+021,0,0=1,0,0\text{proj}_{\vec{b}}\vec{a} = \frac{1(1) + 2(0) + 3(0)}{1^2 + 0^2 + 0^2}\langle 1, 0, 0 \rangle = \langle 1, 0, 0 \rangle
  • Results in a vector with the same direction as b\vec{b} (or opposite if ab<0\vec{a} \cdot \vec{b} < 0)
  • Has a equal to projba=acosθ|\text{proj}_{\vec{b}}\vec{a}| = |\vec{a}|\cos\theta, where θ\theta is the angle between a\vec{a} and b\vec{b}
    • Useful for decomposing vectors into parallel and perpendicular components

Dot product in work problems

  • Applies the dot product to calculate work in physics as the product of the force vector F\vec{F} and the displacement vector d\vec{d}: W=FdW = \vec{F} \cdot \vec{d}
    • Example: If a force F=2,0,0\vec{F} = \langle 2, 0, 0 \rangle N is applied to an object that moves d=3,0,0\vec{d} = \langle 3, 0, 0 \rangle m, then the work done is W=2(3)+0(0)+0(0)=6W = 2(3) + 0(0) + 0(0) = 6 J
  • Simplifies work calculation by accounting for the angle between the force and displacement vectors: W=FdcosθW = |\vec{F}||\vec{d}|\cos\theta
    • Positive work indicates force and displacement are in the same direction (angle < 90°)
    • Negative work indicates force and displacement are in opposite directions (angle > 90°)
    • Zero work indicates force and displacement are perpendicular (angle = 90°)

Vector properties and operations

  • Magnitude of a vector a=a1,a2,a3\vec{a} = \langle a_1, a_2, a_3 \rangle is calculated as a=a12+a22+a32|\vec{a}| = \sqrt{a_1^2 + a_2^2 + a_3^2}
  • are the individual scalar values that make up a vector (e.g., a1a_1, a2a_2, and a3a_3 for a=a1,a2,a3\vec{a} = \langle a_1, a_2, a_3 \rangle)
  • of a vector a\vec{a} by a scalar kk results in ka=ka1,ka2,ka3k\vec{a} = \langle ka_1, ka_2, ka_3 \rangle, changing the vector's magnitude but not its direction (unless k<0k < 0)
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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