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10.3 Applications to area and volume

4 min readaugust 6, 2024

over general regions are powerful tools for calculating areas and volumes. They let us handle complex shapes by breaking them down into smaller pieces and adding them up.

This section focuses on applying double integrals to find areas of 2D regions and volumes of 3D solids. We'll learn how to set up integrals, choose coordinate systems, and interpret results for real-world problems.

Area and Volume Calculation

Calculating Area Using Double Integrals

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  • Calculate the area of a region in the xy-plane by setting up a double integral over the region
    • The double integral RdA\iint_{R} dA gives the area of the region RR
    • The depend on the shape of the region (rectangular, non-rectangular, or )
  • Convert between rectangular and polar coordinates when calculating areas
    • Rectangular coordinates: dA=dxdydA = dxdy
    • Polar coordinates: dA=rdrdθdA = rdrd\theta
  • Determine the order of integration based on the region's boundaries
    • Integrate with respect to yy first if the region is bounded by functions of xx
    • Integrate with respect to xx first if the region is bounded by functions of yy

Volume Calculation Using Double Integrals

  • Calculate the volume of a solid region by integrating a function f(x,y)f(x,y) over a region RR in the xy-plane
    • The double integral Rf(x,y)dA\iint_{R} f(x,y) dA gives the volume of the solid region
    • The function f(x,y)f(x,y) represents the height of the solid at each point (x,y)(x,y) in the region RR
  • Set up the limits of integration based on the region's boundaries in the xy-plane
  • Determine the order of integration based on the region's boundaries
    • Integrate with respect to yy first if the region is bounded by functions of xx
    • Integrate with respect to xx first if the region is bounded by functions of yy

Surface Area and Solid Regions

  • Calculate the of a solid by integrating over the region in the xy-plane
    • The surface area is given by the double integral R1+(zx)2+(zy)2dA\iint_{R} \sqrt{1 + (\frac{\partial z}{\partial x})^2 + (\frac{\partial z}{\partial y})^2} dA
    • The function z=f(x,y)z = f(x,y) represents the surface of the solid
  • Determine the boundaries of the solid region in the xy-plane
    • The solid region is the projection of the surface onto the xy-plane
  • Set up the limits of integration based on the boundaries of the solid region
  • Calculate the volume of a solid region using the or shells
    • Method of disks: Integrate the cross-sectional area of the solid (disks) along the axis of rotation
    • : Integrate the lateral surface area of the solid (shells) along the axis of rotation

Physical Properties

Moment of Inertia

  • Calculate the of a planar region using double integrals
    • The moment of inertia measures the resistance of an object to rotational acceleration
    • For a planar region with density ρ(x,y)\rho(x,y), the moment of inertia about the x-axis is Ix=Ry2ρ(x,y)dAI_x = \iint_{R} y^2 \rho(x,y) dA
    • For a planar region with density ρ(x,y)\rho(x,y), the moment of inertia about the y-axis is Iy=Rx2ρ(x,y)dAI_y = \iint_{R} x^2 \rho(x,y) dA
  • Determine the region RR over which the double integral is evaluated
  • Set up the limits of integration based on the region's boundaries

Center of Mass

  • Find the center of mass (centroid) of a planar region using double integrals
    • The center of mass is the point where the object's mass is evenly distributed
    • For a planar region with density ρ(x,y)\rho(x,y), the x-coordinate of the center of mass is xˉ=Rxρ(x,y)dARρ(x,y)dA\bar{x} = \frac{\iint_{R} x \rho(x,y) dA}{\iint_{R} \rho(x,y) dA}
    • For a planar region with density ρ(x,y)\rho(x,y), the y-coordinate of the center of mass is yˉ=Ryρ(x,y)dARρ(x,y)dA\bar{y} = \frac{\iint_{R} y \rho(x,y) dA}{\iint_{R} \rho(x,y) dA}
  • Determine the region RR over which the double integrals are evaluated
  • Set up the limits of integration based on the region's boundaries

Density Functions

  • Understand the concept of in the context of double integrals
    • A density function ρ(x,y)\rho(x,y) describes the mass per unit area at each point (x,y)(x,y) in a region
    • The total mass of a planar region with density ρ(x,y)\rho(x,y) is given by the double integral Rρ(x,y)dA\iint_{R} \rho(x,y) dA
  • Incorporate density functions into calculations of physical properties
    • Density functions are used in the calculation of moments of inertia and centers of mass
  • Determine the appropriate density function based on the given problem
    • Constant density: ρ(x,y)=ρ0\rho(x,y) = \rho_0
    • Variable density: ρ(x,y)\rho(x,y) is a function of xx and yy

Advanced Geometry

Curved Surfaces

  • Parameterize using
    • A curved surface can be represented by a vector-valued function r(u,v)=x(u,v),y(u,v),z(u,v)\vec{r}(u,v) = \langle x(u,v), y(u,v), z(u,v) \rangle
    • The parameters uu and vv vary over a region DD in the uv-plane
  • Calculate over curved surfaces
    • A surface integral of a function f(x,y,z)f(x,y,z) over a curved surface SS is given by Sf(x,y,z)dS\iint_{S} f(x,y,z) dS
    • The surface element dSdS is determined by the cross product of the partial derivatives of the vector-valued function: dS=ru×rvdudvdS = \left\| \frac{\partial \vec{r}}{\partial u} \times \frac{\partial \vec{r}}{\partial v} \right\| dudv
  • Apply surface integrals to find the area of a curved surface
    • The area of a curved surface SS is given by the surface integral SdS\iint_{S} dS
  • Determine the limits of integration based on the region DD in the parameter space
    • The region DD in the uv-plane corresponds to the domain of the vector-valued function r(u,v)\vec{r}(u,v)
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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