You have 3 free guides left 😟
Unlock your guides
You have 3 free guides left 😟
Unlock your guides

Quadratic equations are a key part of algebra, describing relationships where one variable is squared. They pop up in many real-world situations, from physics to economics. Understanding how to solve them is crucial for tackling more complex math problems.

There are several ways to crack these equations, including , using the , and applying the . Each method has its strengths, and knowing when to use which can save you time and headaches in problem-solving.

Solving Quadratic Equations

Factoring techniques for quadratics

Top images from around the web for Factoring techniques for quadratics
Top images from around the web for Factoring techniques for quadratics
  • Quadratic equations in ax2+bx+c=0ax^2 + bx + c = 0 where aa is not equal to 0 (a0a \neq 0)
  • states that if the product of two factors is zero, then at least one of the factors must be zero (ab=0ab = 0, then either a=0a = 0 or b=0b = 0, or both)
  • involves combining like terms and out common factors
    • Group terms with a common factor and factor out the (GCF) from each group
    • Factor out the GCF from the entire expression if possible (6x2+3x6x^2 + 3x can be factored as 3x(2x+1)3x(2x + 1))
  • Special factoring patterns include and perfect square trinomials
    • formula a2b2=(a+b)(ab)a^2 - b^2 = (a+b)(a-b) can be used to factor expressions like x29=(x+3)(x3)x^2 - 9 = (x+3)(x-3)
    • Perfect square trinomials a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a+b)^2 and a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a-b)^2 factor into the square of a binomial (x2+6x+9=(x+3)2x^2 + 6x + 9 = (x+3)^2)
  • Solving quadratic equations by factoring involves factoring the expression and setting each factor equal to zero
    • Factor the quadratic expression completely
    • Set each factor equal to zero and solve the resulting linear equations to find the solutions (x25x+6=0x^2 - 5x + 6 = 0 factors to (x2)(x3)=0(x-2)(x-3) = 0, so x=2x = 2 or x=3x = 3)
    • These solutions are also known as the of the

Square root property in equations

  • states that if x2=ax^2 = a, then x=±ax = \pm \sqrt{a}
  • Isolating the squared term involves adding or subtracting terms to get the squared term alone on one side of the (x2+4=20x^2 + 4 = 20 becomes x2=16x^2 = 16)
  • Taking the square root of both sides of the equation and simplifying the result if possible (x2=16\sqrt{x^2} = \sqrt{16} becomes x=±4x = \pm 4)
  • Considering both positive and negative solutions is necessary because a squared term can have two square (9=±3\sqrt{9} = \pm 3)

Completing the square method

  • involves rewriting the in the form x2+bx=cx^2 + bx = -c
    • Divide the of xx by 2 and square the result (b2)2(\frac{b}{2})^2
    • Add and subtract (b2)2(\frac{b}{2})^2 to the equation to create a
    • Factor the and isolate the squared term
    • Apply the square root property to solve for xx (x2+6x+5=0x^2 + 6x + 5 = 0 becomes (x+3)2=4(x+3)^2 = 4, so x=3±4=3±2x = -3 \pm \sqrt{4} = -3 \pm 2)
  • of a quadratic equation y=a(xh)2+ky = a(x-h)^2 + k where (h,k)(h, k) is the and x=hx = h is the
  • quadratic equations involves identifying the vertex and , plotting additional points, and connecting them to form a
    • Use the equation or a table of values to find points on the graph
    • The will be symmetric about the axis of symmetry and open upward if a>0a > 0 or downward if a<0a < 0

Quadratic Formula and Applications

Quadratic formula applications

  • x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2-4ac}}{2a} can be used to find solutions for any quadratic equation ax2+bx+c=0ax^2 + bx + c = 0
  • Δ=b24ac\Delta = b^2 - 4ac determines the nature of the solutions
    • If Δ>0\Delta > 0, the equation has two distinct real solutions (x25x+6=0x^2 - 5x + 6 = 0 has Δ=1\Delta = 1, so x=2x = 2 or x=3x = 3)
    • If Δ=0\Delta = 0, the equation has one repeated real solution (x26x+9=0x^2 - 6x + 9 = 0 has Δ=0\Delta = 0, so x=3x = 3)
    • If Δ<0\Delta < 0, the equation has no real solutions, only complex solutions (x2+2x+5=0x^2 + 2x + 5 = 0 has Δ=16\Delta = -16, so no real solutions)
  • Simplifying the solutions by reducing square roots and fractions if possible
  • Applications of quadratic equations involve solving word problems related to , area, and other quadratic relationships
    • Identify the appropriate equation to model the situation, such as the height of a thrown ball h(t)=16t2+64t+5h(t) = -16t^2 + 64t + 5
    • Interpret the solutions in the context of the problem, such as the time at which the ball reaches its maximum height or hits the ground

Additional Concepts in Quadratic Equations

  • A quadratic equation is a specific type of with a highest of 2
  • The coefficients in a quadratic equation are the numerical values that multiply the variables
  • Graphing quadratic equations results in a parabola, which is a U-shaped curve
  • The solutions to a quadratic equation can be found by solving the equation or by identifying where the graph of the function crosses the x-axis
© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.


© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
Glossary
Glossary