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19.1 Definition and basic antiderivatives

3 min readjuly 22, 2024

Antiderivatives and indefinite integrals are like reverse engineering for functions. Instead of finding how fast something changes, we figure out what function could have led to that rate of change. It's like working backwards from speed to distance.

This process is crucial for solving real-world problems. By understanding antiderivatives, we can predict future values, calculate total changes, and solve complex equations in physics, economics, and engineering.

Antiderivatives and Indefinite Integrals

Antiderivatives and derivatives relationship

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  • An of a function f(x)f(x) is a function F(x)F(x) whose derivative is f(x)f(x)
    • If F(x)=f(x)F'(x) = f(x), then F(x)F(x) is an antiderivative of f(x)f(x)
    • Example: If f(x)=2xf(x) = 2x, then F(x)=x2+CF(x) = x^2 + C is an antiderivative of f(x)f(x) because F(x)=2xF'(x) = 2x
  • The process of finding an antiderivative is the opposite of finding a derivative
    • Derivatives calculate the rate of change of a function (f(x)f'(x) represents the slope of the tangent line at each point)
    • Antiderivatives determine a function given its rate of change (F(x)F(x) represents the original function, given the derivative f(x)f(x))

Antiderivatives of basic functions

  • Power rule: If f(x)=xnf(x) = x^n, then an antiderivative of f(x)f(x) is F(x)=xn+1n+1+CF(x) = \frac{x^{n+1}}{n+1} + C, where CC is a constant and n1n \neq -1
    • Example: An antiderivative of f(x)=x3f(x) = x^3 is F(x)=x44+CF(x) = \frac{x^4}{4} + C
    • Example: An antiderivative of f(x)=xf(x) = \sqrt{x} (or x12x^{\frac{1}{2}}) is F(x)=23x32+CF(x) = \frac{2}{3}x^{\frac{3}{2}} + C
  • : If f(x)=exf(x) = e^x, then an antiderivative of f(x)f(x) is F(x)=ex+CF(x) = e^x + C
    • Example: An antiderivative of f(x)=3exf(x) = 3e^x is F(x)=3ex+CF(x) = 3e^x + C
  • :
    • If f(x)=sin(x)f(x) = \sin(x), then an antiderivative of f(x)f(x) is F(x)=cos(x)+CF(x) = -\cos(x) + C
    • If f(x)=cos(x)f(x) = \cos(x), then an antiderivative of f(x)f(x) is F(x)=sin(x)+CF(x) = \sin(x) + C
    • If f(x)=sec2(x)f(x) = \sec^2(x), then an antiderivative of f(x)f(x) is F(x)=tan(x)+CF(x) = \tan(x) + C
    • Example: An antiderivative of f(x)=2sin(x)f(x) = 2\sin(x) is F(x)=2cos(x)+CF(x) = -2\cos(x) + C

Rules for complex antiderivatives

  • : If F(x)F(x) is an antiderivative of f(x)f(x), then kF(x)kF(x) is an antiderivative of kf(x)kf(x), where kk is a constant
    • Example: If an antiderivative of f(x)=x2f(x) = x^2 is F(x)=x33+CF(x) = \frac{x^3}{3} + C, then an antiderivative of 3x23x^2 is 3(x33+C)=x3+C3(\frac{x^3}{3} + C) = x^3 + C
    • Example: If an antiderivative of f(x)=sin(x)f(x) = \sin(x) is F(x)=cos(x)+CF(x) = -\cos(x) + C, then an antiderivative of 5sin(x)5\sin(x) is 5cos(x)+C-5\cos(x) + C
  • : If F(x)F(x) is an antiderivative of f(x)f(x) and G(x)G(x) is an antiderivative of g(x)g(x), then F(x)+G(x)F(x) + G(x) is an antiderivative of f(x)+g(x)f(x) + g(x)
    • Example: If an antiderivative of f(x)=x2f(x) = x^2 is F(x)=x33+CF(x) = \frac{x^3}{3} + C and an antiderivative of g(x)=sin(x)g(x) = \sin(x) is G(x)=cos(x)+CG(x) = -\cos(x) + C, then an antiderivative of x2+sin(x)x^2 + \sin(x) is x33cos(x)+C\frac{x^3}{3} - \cos(x) + C
    • Example: An antiderivative of f(x)=x3+exf(x) = x^3 + e^x is F(x)=x44+ex+CF(x) = \frac{x^4}{4} + e^x + C

Concept of indefinite integrals

  • An is the set of all antiderivatives of a given function
    • The indefinite integral of f(x)f(x) is denoted as f(x)dx\int f(x) \, dx
    • The variable of integration (usually xx) is written as dxdx to indicate the variable with respect to which the integration is performed
    • Example: x2dx\int x^2 \, dx represents the set of all antiderivatives of x2x^2
  • The result of an indefinite integral includes a constant of integration, typically denoted as CC
    • Example: x2dx=x33+C\int x^2 \, dx = \frac{x^3}{3} + C, where CC is an arbitrary constant
    • Example: exdx=ex+C\int e^x \, dx = e^x + C
  • The constant of integration represents a family of functions that differ by a constant value
    • The specific value of CC is determined by initial conditions or boundary conditions when solving problems involving definite integrals or differential equations
    • Example: If f(x)dx=F(x)+C\int f(x) \, dx = F(x) + C and F(1)=3F(1) = 3, then C=3F(1)C = 3 - F(1)
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AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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