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5.1 Power rule and constant rule

2 min readjuly 22, 2024

The and are key tools for finding derivatives of polynomials. These rules simplify the process of differentiation by providing straightforward steps for each term in a .

By applying these rules, you can quickly determine how a polynomial function changes. The power rule reduces the degree of each term, while the constant rule eliminates constant terms, resulting in a new polynomial that represents the rate of change of the original function.

Power Rule and Constant Rule

Power rule for polynomial derivatives

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  • States for a function f(x)=xnf(x) = x^n, its derivative is [f(x)](https://www.fiveableKeyTerm:f(x))=nxn1[f'(x)](https://www.fiveableKeyTerm:f'(x)) = nx^{n-1}
    • f(x)=x4f(x) = x^4, then f(x)=4x3f'(x) = 4x^3
  • To apply to a term in a polynomial, multiply coefficient by exponent and decrease exponent by 1
    • f(x)=3x5f(x) = 3x^5, then f(x)=35x51=15x4f'(x) = 3 \cdot 5x^{5-1} = 15x^4
  • When polynomial has multiple terms, apply power rule to each term separately
    • f(x)=2x3+4x25xf(x) = 2x^3 + 4x^2 - 5x, then f(x)=23x31+42x2151x11=6x2+8x5f'(x) = 2 \cdot 3x^{3-1} + 4 \cdot 2x^{2-1} - 5 \cdot 1x^{1-1} = 6x^2 + 8x - 5

Constant rule in differentiation

  • States function is always 0
    • f(x)=7f(x) = 7, then f(x)=0f'(x) = 0
  • Applies to any constant term in a polynomial function
    • f(x)=3x2+5f(x) = 3x^2 + 5, then derivative of constant term 5 is 0
  • Constant terms remain unchanged in the derivative (2x3+42x^3 + 4 becomes 6x2+06x^2 + 0)

Combining rules for polynomials

  • When differentiating a polynomial, apply power rule to each term with a variable and constant rule to constant terms
    • f(x)=4x32x+6f(x) = 4x^3 - 2x + 6, then f(x)=43x3121x11+0=12x22f'(x) = 4 \cdot 3x^{3-1} - 2 \cdot 1x^{1-1} + 0 = 12x^2 - 2
  • Add derivatives of each term together to find final derivative of polynomial
    • (3x4x2+2x5)=12x32x+20(3x^4 - x^2 + 2x - 5)' = 12x^3 - 2x + 2 - 0

Polynomial degree vs derivative

  • is highest exponent of variable
    • f(x)=3x4+2x25x+1f(x) = 3x^4 + 2x^2 - 5x + 1, degree is 4
  • When differentiating, is one less than original polynomial
    • f(x)=3x4+2x25x+1f(x) = 3x^4 + 2x^2 - 5x + 1, then f(x)=12x3+4x5f'(x) = 12x^3 + 4x - 5, which has degree 3
  • Relationship holds for all polynomials, as power rule decreases exponent of each term by 1
    • (7x54x3+6x)=35x412x2+6(7x^5 - 4x^3 + 6x)' = 35x^4 - 12x^2 + 6, degree reduced from 5 to 4
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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