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5.3 Projectile Motion

2 min readjune 24, 2024

is all about objects flying through the air. It's like throwing a ball, but with math! We'll look at how things move in arcs and why they follow those paths.

Knowing projectile motion helps us understand everything from sports to space travel. We'll learn how to predict where things will land and how high they'll go, using some cool equations and concepts.

Projectile Motion

Properties of projectile motion

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  • Projectile motion describes the movement of an object launched into the air at an angle (projectile)
    • The curved path followed by the projectile is its
      • In the absence of , the trajectory forms a
  • Horizontal and vertical components of projectile motion can be analyzed independently
    • remains constant throughout the motion (assuming no air resistance)
      • No acceleration acts in the horizontal direction
    • changes due to the constant downward (g=9.81m/s2g = 9.81 m/s^2)
  • The is the same for both horizontal and vertical components of motion
  • (magnitude and direction) determines the projectile's trajectory

Calculations with kinematic equations

  • allow calculation of various aspects of projectile motion
    • : x=v0cos(θ)tx = v_0 \cos(\theta) t
      • v0v_0 = initial velocity, θ\theta = , tt = time of flight
    • : y=v0sin(θ)t12gt2y = v_0 \sin(\theta) t - \frac{1}{2}gt^2
      • gg = acceleration due to gravity
  • resolves initial velocity into horizontal and vertical components
    • Horizontal component: v0x=v0cos(θ)v_{0x} = v_0 \cos(\theta)
    • Vertical component: v0y=v0sin(θ)v_{0y} = v_0 \sin(\theta)
    • Position and velocity at any time found by treating components independently

Range and height of projectiles

  • is the horizontal distance traveled by a projectile before hitting the ground
    • Range formula: R=v02sin(2θ)gR = \frac{v_0^2 \sin(2\theta)}{g}
      • Maximum range occurs at a launch angle of 45°
  • is the highest vertical distance reached during the projectile's flight
    • Maximum height formula: hmax=v02sin2(θ)2gh_{max} = \frac{v_0^2 \sin^2(\theta)}{2g}
    • Maximum height occurs at half the total time of flight
      • Time to reach maximum height: tmax=v0sin(θ)gt_{max} = \frac{v_0 \sin(\theta)}{g}
  • in projectile motion: The path of ascent mirrors the path of descent in ideal conditions

Fundamental principles and applications

  • govern projectile motion, explaining the forces and accelerations involved
  • Air resistance affects real-world projectile motion, causing deviations from ideal parabolic trajectories
  • , the study of projectile motion, has applications in various fields including sports, military, and forensics
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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