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14.3 Relative Strengths of Acids and Bases

3 min readjune 25, 2024

Acid-base strength and equilibrium are crucial concepts in chemistry. They help us understand how substances interact in solution, influencing and chemical reactions. Knowing how to compare acid and base strengths allows us to predict and control these interactions.

Molecular structure plays a key role in determining acid-base strength. Factors like , resonance, and affect how easily substances donate or accept protons. This knowledge is essential for understanding chemical behavior and solving equilibrium problems.

Acid-Base Strength and Equilibrium

Acid vs base strength comparisons

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  • (KaK_a) quantifies acid strength higher KaK_a indicates stronger acid (HCl vs CH3COOH)
  • (KbK_b) quantifies base strength higher KbK_b indicates stronger base (NaOH vs NH3)
  • pKapK_a and pKbpK_b scales are negative logarithms of KaK_a and KbK_b lower pKapK_a indicates stronger acid, lower pKbpK_b indicates stronger base
  • related by Ka×Kb=KwK_a \times K_b = K_w, where KwK_w is ionization constant of water (1.0×10141.0 \times 10^{-14} at 25°C)
  • is the process by which an acid releases a proton in solution, influencing its strength

Molecular structure in acid-base strength

  • Inductive effects influence strength (halogens, nitro) stabilize conjugate base making acid stronger, (alkyl) destabilize conjugate base making acid weaker
  • influence strength stabilization of conjugate base makes acid stronger (carboxylic acids, phenols) due to charge delocalization
  • of atom bonded to acidic hydrogen affects strength sp2sp^2 or spsp hybridized atoms form stronger acids than sp3sp^3 due to greater s-character in bonding orbital
  • of atom bonded to acidic hydrogen affects strength more electronegative atoms (oxygen, nitrogen) form stronger acids than less electronegative (carbon)
  • occurs when a solvent limits the strength of an acid or base, making very strong acids or bases appear equally strong in that solvent

Weak acid-base equilibrium problems

  1. Write acid-base equilibrium expression and corresponding KaK_a or KbK_b expression
    • : HA+H2OH3O++AHA + H_2O \rightleftharpoons H_3O^+ + A^-, Ka=[H3O+][A][HA]K_a = \frac{[H_3O^+][A^-]}{[HA]}
    • : B+H2OBH++OHB + H_2O \rightleftharpoons BH^+ + OH^-, Kb=[BH+][OH][B]K_b = \frac{[BH^+][OH^-]}{[B]}
  2. Use initial, change, equilibrium (ICE) table to set up equilibrium concentrations
    • Initial concentrations based on given problem
    • Change in concentrations determined by reaction stoichiometry
    • Equilibrium concentrations are sum of initial and change values
  3. Substitute equilibrium concentrations into KaK_a or KbK_b expression and solve for unknown variable
    • If necessary, use approximation x<<[HA]0x << [HA]_0 or x<<[B]0x << [B]_0 to simplify calculation, where xx is change in concentration and [HA]0[HA]_0 or [B]0[B]_0 is initial concentration of acid or base
  4. Calculate pH of solution using equilibrium concentration of H3O+H_3O^+ or OHOH^-
    • pH=log[H3O+]pH = -\log{[H_3O^+]} and [pOH](https://www.fiveableKeyTerm:pOH)=log[OH][pOH](https://www.fiveableKeyTerm:pOH) = -\log{[OH^-]}
    • pH+pOH=14pH + pOH = 14 at 25°C

Advanced Acid-Base Concepts

  • Buffer solutions resist changes in pH when small amounts of acid or base are added
  • The relates pH to the concentrations of a weak acid and its conjugate base in a
  • occurs when water molecules react with each other to produce hydronium and hydroxide ions, maintaining a constant ion product in pure water
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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