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3.2 Vector Addition and Subtraction: Graphical Methods

3 min readjune 18, 2024

addition and subtraction are key skills for understanding forces and motion. These techniques allow us to combine or compare multiple vectors, which represent quantities with both and .

We'll explore methods like head-to- and parallelogram for adding vectors, as well as how to calculate vectors. We'll also learn to break vectors into and reconstruct them, essential for solving real-world physics problems.

Vector Addition and Subtraction

Vector addition and subtraction techniques

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  • for vector addition connects the tail of the second vector to the head of the first vector, then draws the from the tail of the first to the head of the last (displacement, velocity)
    • Reverse the direction of the vector being subtracted for , place the tail of the reversed vector at the head of the first vector, and draw the resultant from the tail of the first to the head of the reversed vector (force, acceleration)
  • for vector addition draws the two vectors with their tails connected, completes a parallelogram by drawing lines parallel to each vector, and the is the diagonal from the connected tails to the opposite corner (force, velocity)
  • for vector addition arranges the vectors head-to-tail to form a triangle, and the resultant vector is the side that completes the triangle from the tail of the first vector to the head of the last (displacement, acceleration)
  • These methods are performed within a , which provides a reference frame for vector operations

Resultant vector calculations

  • Measure the of the resultant vector using a ruler and convert the length to the appropriate scale based on the given vector magnitudes (5 cm = 10 N)
  • Determine the direction of the resultant vector by measuring the angle between the resultant and a reference axis (positive x-axis) using a protractor (30° above the horizontal)
  • Apply the to calculate the magnitude of the resultant vector from its components R=Rx2+Ry2R = \sqrt{R_x^2 + R_y^2} (3 N horizontal, 4 N vertical, R=32+42=5R = \sqrt{3^2 + 4^2} = 5 N)
  • Use the function to find the angle between the resultant vector and the horizontal axis θ=tan1(RyRx)\theta = \tan^{-1} \left(\frac{R_y}{R_x}\right) (3 N horizontal, 4 N vertical, θ=tan1(43)53°\theta = \tan^{-1} \left(\frac{4}{3}\right) \approx 53°)
  • Express the resultant using , which includes both magnitude and direction information

Vector component resolution

  • Resolve a vector into its by determining the angle between the vector and the horizontal axis using a protractor (30° above the horizontal)
  • Calculate the using the Ax=AcosθA_x = A \cos \theta (10 N at 30°, Ax=10cos30°8.7A_x = 10 \cos 30° \approx 8.7 N)
  • Calculate the using the Ay=AsinθA_y = A \sin \theta (10 N at 30°, Ay=10sin30°=5A_y = 10 \sin 30° = 5 N)
  • Reconstruct a vector from its components by applying the Pythagorean theorem to find the magnitude A=Ax2+Ay2A = \sqrt{A_x^2 + A_y^2} (8.7 N horizontal, 5 N vertical, A=8.72+5210A = \sqrt{8.7^2 + 5^2} \approx 10 N)
  • Use the arctangent function to find the angle between the reconstructed vector and the horizontal axis θ=tan1(AyAx)\theta = \tan^{-1} \left(\frac{A_y}{A_x}\right) (8.7 N horizontal, 5 N vertical, θ=tan1(58.7)30°\theta = \tan^{-1} \left(\frac{5}{8.7}\right) \approx 30°)

Vector and Scalar Quantities

  • Vectors have both magnitude and direction, while a only has magnitude
  • Unit vectors are vectors with a magnitude of 1 and are used to indicate direction
  • occurs when the vector sum of all forces acting on an object is zero, resulting in no net force
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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