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4.7 Further Applications of Newton’s Laws of Motion

3 min readjune 18, 2024

govern complex force systems, from suspension bridges to sliding blocks. By identifying all forces, determining through vector addition, and applying F=ma, we can solve for unknown quantities in various scenarios.

Accelerating reference frames introduce the concept of , affecting how forces are perceived. This is evident in elevators and situations. Understanding inertial vs. non-inertial frames helps analyze motion in these dynamic environments.

Complex Systems and Accelerating Frames

Newton's laws for complex force systems

  • Identify all forces acting on an object
    • opposes the force of the object on the surface
    • acts along strings, ropes, or cables (suspension bridges)
    • opposes the relative motion between surfaces (sliding blocks)
    • are external forces acting on the object (pushing a cart)
  • Determine the net force using vector addition
    • Resolve forces into horizontal and vertical components
    • Add force components in each direction (xx and yy) to find net force
  • Apply : Fnet=ma\vec{F}_{net} = m\vec{a}
    • Relate the net force to the object's mass and acceleration ()
  • Solve for unknown quantities using algebra and trigonometry

Motion in accelerating reference frames

  • Understand the concept of apparent weight
    • Apparent weight is the force felt by an object in an
    • In an , apparent weight is affected by the elevator's acceleration ( during freefall)
  • Apply Newton's second law in accelerating frames
    • Consider the acceleration of the frame when determining the net force
    • For an elevator: Fnet=m(ag)\vec{F}_{net} = m(\vec{a} - \vec{g}), where a\vec{a} is the elevator's acceleration (emergency braking)
  • Analyze forces in accelerating frames
    • Identify the forces acting on an object in the accelerating frame (tension in elevator cables)
    • Determine the direction and magnitude of the acceleration
  • Distinguish between inertial and non-inertial reference frames
    • Inertial reference frames are those in which Newton's laws hold without modification
    • Non-inertial reference frames require the consideration of fictitious forces

Circular Motion and Centripetal Force

  • Understand the concept of centripetal force
    • Centripetal force is the net force required to keep an object moving in a circular path
    • It is always directed toward the center of the circle
  • Calculate centripetal force: Fc=mv2rF_c = \frac{mv^2}{r}
    • Where mm is mass, vv is velocity, and rr is radius of the circular path
  • Identify sources of centripetal force in various scenarios (tension in a swinging pendulum)

Integrating Kinematics and Dynamics

Kinematics and force in dynamics problems

  • Understand the relationship between and
    • Kinematics describes motion without considering forces ()
    • Dynamics analyzes the forces causing motion ()
  • Use to describe motion
    • v=v0+atv = v_0 + at (acceleration of a car)
    • x=x0+v0t+12at2x = x_0 + v_0t + \frac{1}{2}at^2 (position of a falling object)
    • v2=v02+2a(xx0)v^2 = v_0^2 + 2a(x - x_0) (speed at the end of a ramp)
  • Combine kinematic equations with Newton's second law
    • Relate acceleration to net force and mass
    • Solve for unknown quantities by substituting kinematic equations into force equations
  • Solve multi-step problems
    1. Identify given information and unknowns
    2. Break the problem into smaller steps
    3. Apply appropriate equations at each step
    4. Use results from previous steps to solve subsequent steps (projectile launched at an angle)

Impulse, Momentum, Work, and Energy

  • Understand the concept of and its relation to
    • is the change in momentum of an object
    • Impulse-momentum theorem: FΔt=mΔvF\Delta t = m\Delta v
  • Define momentum as the product of mass and velocity: p=mvp = mv
  • Explore the concept of as force applied over a distance: W=FdW = F \cdot d
  • Introduce as the capacity to do work
    • Kinetic energy: KE=12mv2KE = \frac{1}{2}mv^2
    • Potential energy: PE=mghPE = mgh (for gravitational potential energy)
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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