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First-order differential equations are the building blocks of more complex systems. They come in two main flavors: separable and linear. Knowing how to spot and solve these equations is key to tackling real-world problems in science and engineering.

let you split variables, while linear ones follow a standard form. Both types have specific solving methods: and , respectively. Mastering these techniques opens doors to understanding more advanced differential equations and their applications.

Classifying Differential Equations

Types of First-Order Differential Equations

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  • First-order differential equations involve a function and its first derivative, typically in the form dydx=f(x,y)\frac{dy}{dx} = f(x,y)
  • Separable differential equations take the form dydx=g(x)h(y)\frac{dy}{dx} = g(x)h(y), allowing variables x and y to be separated onto different sides
  • Linear first-order differential equations have the standard form dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x), where P(x) and Q(x) are functions of x only
  • Non- may still be separable if rearranged into the separable form
  • Homogeneous linear first-order equations follow the form dydx+P(x)y=0\frac{dy}{dx} + P(x)y = 0 where Q(x) = 0

Identifying Equation Types

  • Presence of y and terms in a product indicates a non-linear equation
  • Recognition of equation forms guides selection of appropriate solution methods
  • Separation of variables method applied for separable equations
  • Integrating factor method used for linear equations
  • Careful examination of equation structure reveals classification (linear, separable, non-linear)
  • Practice with various equation forms enhances recognition skills
  • Some equations may be transformed into separable or linear forms through or manipulation

Solving Separable Equations

Separation of Variables Method

  • Rearrange equation to isolate y and dy on one side, x and dx on the other
  • Separated equation takes the form 1h(y)dy=g(x)dx\frac{1}{h(y)}dy = g(x)dx
  • Integrate both sides: 1h(y)dy=g(x)dx+C\int\frac{1}{h(y)}dy = \int g(x)dx + C
  • Resulting equation typically in implicit form F(y)=G(x)+CF(y) = G(x) + C
  • F(y) and G(x) represent antiderivatives of 1h(y)\frac{1}{h(y)} and g(x) respectively
  • In some cases, solve explicitly for y as a function of x, yielding y=f(x,C)y = f(x,C)
  • C represents the constant of integration

Considerations and Examples

  • Watch for potential division by zero when separating variables (may lead to extraneous or lost solutions)
  • Example: Solve dydx=xy\frac{dy}{dx} = xy
    • Separate variables: 1ydy=xdx\frac{1}{y}dy = xdx
    • Integrate: lny=12x2+C\ln|y| = \frac{1}{2}x^2 + C
    • Solve for y: y=±e12x2+Cy = \pm e^{\frac{1}{2}x^2 + C} or y=Ae12x2y = Ae^{\frac{1}{2}x^2} where A is a new constant
  • Example: Solve dydx=xy2\frac{dy}{dx} = \frac{x}{y^2}
    • Separate variables: y2dy=xdxy^2dy = xdx
    • Integrate: 13y3=12x2+C\frac{1}{3}y^3 = \frac{1}{2}x^2 + C
    • Implicit form is the final solution

Solving Linear Equations

Integrating Factor Method

  • Transform standard form dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x) into an exact differential equation
  • Define integrating factor μ(x)=eP(x)dx\mu(x) = e^{\int P(x)dx}
  • Multiply both sides of original equation by μ(x)
  • Resulting equation: ddx[μ(x)y]=μ(x)Q(x)\frac{d}{dx}[\mu(x)y] = \mu(x)Q(x)
  • Integrate both sides: d[μ(x)y]=μ(x)Q(x)dx\int d[\mu(x)y] = \int \mu(x)Q(x)dx
  • Solve for y to get : y=1μ(x)[μ(x)Q(x)dx+C]y = \frac{1}{\mu(x)}[\int \mu(x)Q(x)dx + C]

Application and Examples

  • Method works for all linear first-order differential equations (homogeneous and non-homogeneous)
  • Example: Solve dydx+2xy=x\frac{dy}{dx} + 2xy = x
    • Identify P(x) = 2x and Q(x) = x
    • Calculate integrating factor: μ(x)=e2xdx=ex2\mu(x) = e^{\int 2xdx} = e^{x^2}
    • Multiply equation by μ(x): ex2dydx+2xex2y=xex2e^{x^2}\frac{dy}{dx} + 2xe^{x^2}y = xe^{x^2}
    • Integrate: ex2y=xex2dx+C=12ex2+Ce^{x^2}y = \int xe^{x^2}dx + C = \frac{1}{2}e^{x^2} + C
    • Solve for y: y=12+Cex2y = \frac{1}{2} + Ce^{-x^2}
  • Example: Solve dydxy=ex\frac{dy}{dx} - y = e^x
    • Integrating factor: μ(x)=ex\mu(x) = e^{-x}
    • General solution: y=ex+Cexy = e^x + Ce^x

General vs Particular Solutions

General Solutions

  • Include arbitrary constant C, representing entire family of solutions
  • For separable equations, typically in form F(y)=G(x)+CF(y) = G(x) + C or y=f(x,C)y = f(x,C)
  • In linear equations, take form y=1μ(x)[μ(x)Q(x)dx+C]y = \frac{1}{\mu(x)}[\int \mu(x)Q(x)dx + C]
  • Represent all possible solutions to the differential equation
  • Graphically depicted as a family of curves in the xy-plane

Particular Solutions and Initial Value Problems

  • Obtained by using to determine specific value of constant C
  • Initial value problem (IVP) finds satisfying given initial condition y(x0)=y0y(x_0) = y_0
  • Process to find particular solution:
    1. Substitute initial condition into general solution
    2. Solve for C
    3. Substitute C value back into general solution
  • Example: For y=12+Cex2y = \frac{1}{2} + Ce^{-x^2} with initial condition y(0) = 1
    1. Substitute: 1=12+C1 = \frac{1}{2} + C
    2. Solve: C=12C = \frac{1}{2}
    3. Particular solution: y=12+12ex2y = \frac{1}{2} + \frac{1}{2}e^{-x^2}
  • theorem states conditions for unique IVP solution
  • Graphical representations (direction fields, solution curves) provide insights into solution behavior
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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