Complex functions can behave strangely at certain points. These points, called singularities, are where the function isn't smooth or well-defined. Understanding singularities is key to grasping complex analysis.
Poles are a special type of singularity where the function grows infinitely large. They're crucial for calculating integrals using the residue theorem , which is the main focus of this chapter on contour integration.
Types of Singularities
Isolated Singularities
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Singularity a point where a complex function fails to be analytic (differentiable)
Isolated singularity a singularity z 0 z_0 z 0 such that f ( z ) f(z) f ( z ) is analytic in some deleted neighborhood of z 0 z_0 z 0
Deleted neighborhood excludes the point z 0 z_0 z 0 itself
Three types of isolated singularities poles, removable singularities, and essential singularities
Determining the type of isolated singularity involves examining the limit of ( z − z 0 ) n f ( z ) (z-z_0)^nf(z) ( z − z 0 ) n f ( z ) as z → z 0 z \to z_0 z → z 0 for various values of n n n
Non-Isolated Singularities
Branch point a type of non-isolated singularity
Occurs when a multi-valued function (square root, logarithm) is not analytic in any deleted neighborhood of the point
Example of a branch point f ( z ) = z f(z) = \sqrt{z} f ( z ) = z has a branch point at z = 0 z=0 z = 0
No matter how small a deleted neighborhood around 0 0 0 is chosen, f ( z ) f(z) f ( z ) will not be analytic due to the multiple values of the square root
Removable Singularities and Poles
Removable singularity a singularity z 0 z_0 z 0 where the limit of f ( z ) f(z) f ( z ) as z → z 0 z \to z_0 z → z 0 exists and is finite
The function can be redefined at z 0 z_0 z 0 to make it analytic there
Example f ( z ) = sin z z f(z) = \frac{\sin z}{z} f ( z ) = z s i n z has a removable singularity at z = 0 z=0 z = 0 since lim z → 0 sin z z = 1 \lim_{z \to 0} \frac{\sin z}{z} = 1 lim z → 0 z s i n z = 1
Pole a singularity z 0 z_0 z 0 where the limit of ∣ f ( z ) ∣ |f(z)| ∣ f ( z ) ∣ as z → z 0 z \to z_0 z → z 0 is infinite
The function "blows up" to infinity near the pole
Example f ( z ) = 1 z f(z) = \frac{1}{z} f ( z ) = z 1 has a pole at z = 0 z=0 z = 0 since lim z → 0 ∣ 1 z ∣ = ∞ \lim_{z \to 0} |\frac{1}{z}| = \infty lim z → 0 ∣ z 1 ∣ = ∞
Essential Singularities
Essential singularity a singularity that is neither removable nor a pole
The limit of f ( z ) f(z) f ( z ) as z → z 0 z \to z_0 z → z 0 does not exist, even when allowing infinite values
Characterized by highly erratic behavior near the singularity
The function values can approach any complex number or infinity in any neighborhood of z 0 z_0 z 0
Example f ( z ) = e 1 z f(z) = e^{\frac{1}{z}} f ( z ) = e z 1 has an essential singularity at z = 0 z=0 z = 0
As z → 0 z \to 0 z → 0 , f ( z ) f(z) f ( z ) oscillates wildly between very large and very small values
Pole Characteristics
Poles and Their Orders
Pole a singularity z 0 z_0 z 0 where the limit of ∣ f ( z ) ∣ |f(z)| ∣ f ( z ) ∣ as z → z 0 z \to z_0 z → z 0 is infinite
Order of a pole the smallest positive integer n n n such that lim z → z 0 ( z − z 0 ) n f ( z ) \lim_{z \to z_0} (z-z_0)^nf(z) lim z → z 0 ( z − z 0 ) n f ( z ) is finite and nonzero
A pole of order 1 1 1 is called a simple pole
Higher order poles (n ≥ 2 n \geq 2 n ≥ 2 ) are multiple poles
Example f ( z ) = 1 ( z − 1 ) 2 f(z) = \frac{1}{(z-1)^2} f ( z ) = ( z − 1 ) 2 1 has a pole of order 2 2 2 (double pole) at z = 1 z=1 z = 1
lim z → 1 ( z − 1 ) 2 f ( z ) = 1 \lim_{z \to 1} (z-1)^2f(z) = 1 lim z → 1 ( z − 1 ) 2 f ( z ) = 1 , which is finite and nonzero
Laurent Series and Residues
Laurent series an expansion of a complex function f ( z ) f(z) f ( z ) in powers of ( z − z 0 ) (z-z_0) ( z − z 0 ) , valid in an annulus around z 0 z_0 z 0
Generalizes Taylor series to functions with singularities
f ( z ) = ∑ n = − ∞ ∞ a n ( z − z 0 ) n f(z) = \sum_{n=-\infty}^{\infty} a_n(z-z_0)^n f ( z ) = ∑ n = − ∞ ∞ a n ( z − z 0 ) n , where a n = 1 2 π i ∮ C f ( z ) ( z − z 0 ) n + 1 d z a_n = \frac{1}{2\pi i} \oint_C \frac{f(z)}{(z-z_0)^{n+1}} dz a n = 2 πi 1 ∮ C ( z − z 0 ) n + 1 f ( z ) d z
Residue the coefficient a − 1 a_{-1} a − 1 of the 1 z − z 0 \frac{1}{z-z_0} z − z 0 1 term in the Laurent series
Measures the "strength" of the singularity at z 0 z_0 z 0
For a pole of order n n n , the residue is given by 1 ( n − 1 ) ! lim z → z 0 d n − 1 d z n − 1 [ ( z − z 0 ) n f ( z ) ] \frac{1}{(n-1)!} \lim_{z \to z_0} \frac{d^{n-1}}{dz^{n-1}} [(z-z_0)^nf(z)] ( n − 1 )! 1 lim z → z 0 d z n − 1 d n − 1 [( z − z 0 ) n f ( z )]
Example for f ( z ) = 1 z 2 f(z) = \frac{1}{z^2} f ( z ) = z 2 1 , the Laurent series around z = 0 z=0 z = 0 is 1 z 2 + 0 + 0 + ⋯ \frac{1}{z^2} + 0 + 0 + \cdots z 2 1 + 0 + 0 + ⋯
The residue at z = 0 z=0 z = 0 is 0 0 0 , the coefficient of 1 z \frac{1}{z} z 1