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2.3 Arc Length and Curvature

2 min readjuly 25, 2024

Arc length and are crucial concepts in understanding curves in space. They allow us to measure distances along curves and describe their shapes mathematically, providing tools for analyzing motion and geometry in three dimensions.

These concepts build on earlier ideas of vectors and derivatives, extending them to more complex curves. By learning to calculate arc length and reparameterize curves, we gain insights into , motion, and the behavior of objects moving along curved paths.

Arc Length and Parameterization

Arc length of space curves

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  • for calculates distance traveled along curve s=t1t2(dxdt)2+(dydt)2+(dzdt)2dts = \int_{t_1}^{t_2} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2 + (\frac{dz}{dt})^2} dt
  • Calculate arc length by:
    1. Express curve in parametric form (x(t), y(t), z(t))
    2. Compute derivatives dxdt\frac{dx}{dt}, dydt\frac{dy}{dt}, dzdt\frac{dz}{dt}
    3. Substitute into arc length formula
    4. Evaluate
  • Adapt formula for specific cases:
    • omit z component s=t1t2(dxdt)2+(dydt)2dts = \int_{t_1}^{t_2} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} dt
    • Functions y = f(x) use s=x1x21+(f(x))2dxs = \int_{x_1}^{x_2} \sqrt{1 + (f'(x))^2} dx
  • Examples: helix, circular arc, parabola

Arc length parameter for reparameterization

  • represents curve using distance traveled ensures unit speed
  • Derive arc length parameter:
    1. Start with arc length formula
    2. Define s(t)=t0t(dxdu)2+(dydu)2+(dzdu)2dus(t) = \int_{t_0}^t \sqrt{(\frac{dx}{du})^2 + (\frac{dy}{du})^2 + (\frac{dz}{du})^2} du
    3. Invert function to get t(s)
    4. Substitute t(s) into original parametric equations
  • Applications simplify calculations describe motion at constant speed (, )

Concept of curvature

  • Curvature measures how quickly curve changes direction inversely proportional to radius
  • Formula: κ=r(t)×r(t)r(t)3\kappa = \frac{|\mathbf{r}'(t) \times \mathbf{r}''(t)|}{|\mathbf{r}'(t)|^3}
  • Geometric interpretation:
    • Straight lines zero curvature
    • Circles constant curvature
    • Smaller radius sharper turns
  • Osculating circle best approximates curve at point radius reciprocal of curvature
  • Examples: , ,

Unit vectors of curves

  • Unit T(t)=r(t)r(t)\mathbf{T}(t) = \frac{\mathbf{r}'(t)}{|\mathbf{r}'(t)|} points in direction of motion
  • Unit N(t)=T(t)T(t)\mathbf{N}(t) = \frac{\mathbf{T}'(t)}{|\mathbf{T}'(t)|} perpendicular to tangent
  • B(t)=T(t)×N(t)\mathbf{B}(t) = \mathbf{T}(t) \times \mathbf{N}(t) perpendicular to both tangent and normal
  • formed by T, N, B vectors provides moving coordinate system
  • Vector relationships:
    • T=κN\mathbf{T}' = \kappa \mathbf{N}
    • N=κT+τB\mathbf{N}' = -\kappa \mathbf{T} + \tau \mathbf{B}
    • B=τN\mathbf{B}' = -\tau \mathbf{N}
  • τ\tau measures curve twisting out of plane
  • Applications: robotics, , navigation systems
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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