3.3 Equilibrium of rigid bodies in two and three dimensions
4 min read•july 30, 2024
Equilibrium of rigid bodies is all about balance. In 2D, we need zero forces in x and y directions, plus zero total moment. In 3D, it's the same, but we add a z-direction and moments around all three axes.
Free-body diagrams are key to solving these problems. They show all forces and moments acting on an isolated body. Whether forces meet at one point or not, we use equilibrium equations to find unknown forces and keep things steady.
Equilibrium of Rigid Bodies
Conditions for Equilibrium in Two and Three Dimensions
Top images from around the web for Conditions for Equilibrium in Two and Three Dimensions
Applications of Statics, Including Problem-Solving Strategies · Physics View original
Is this image relevant?
Conditions for Equilibrium | Boundless Physics View original
Is this image relevant?
Applications of Statics, Including Problem-Solving Strategies · Physics View original
Is this image relevant?
Applications of Statics, Including Problem-Solving Strategies · Physics View original
Is this image relevant?
Conditions for Equilibrium | Boundless Physics View original
Is this image relevant?
1 of 3
Top images from around the web for Conditions for Equilibrium in Two and Three Dimensions
Applications of Statics, Including Problem-Solving Strategies · Physics View original
Is this image relevant?
Conditions for Equilibrium | Boundless Physics View original
Is this image relevant?
Applications of Statics, Including Problem-Solving Strategies · Physics View original
Is this image relevant?
Applications of Statics, Including Problem-Solving Strategies · Physics View original
Is this image relevant?
Conditions for Equilibrium | Boundless Physics View original
Is this image relevant?
1 of 3
Equilibrium of a rigid body occurs when the sum of all forces acting on the body is zero and the sum of all moments about any point is zero
In two dimensions, the conditions for equilibrium are:
ΣFx = 0 (sum of forces in the x-direction equals zero)
ΣFy = 0 (sum of forces in the y-direction equals zero)
ΣM = 0 (sum of moments about any point equals zero)
In three dimensions, the conditions for equilibrium are:
ΣFx = 0 (sum of forces in the x-direction equals zero)
ΣFy = 0 (sum of forces in the y-direction equals zero)
ΣFz = 0 (sum of forces in the z-direction equals zero)
ΣMx = 0 (sum of moments about the x-axis equals zero)
ΣMy = 0 (sum of moments about the y-axis equals zero)
ΣMz = 0 (sum of moments about the z-axis equals zero)
Static Equilibrium and Free-Body Diagrams
A rigid body is considered to be in when it is at rest or moving with a constant velocity, and the and net moment acting on the body are zero
The concept of free-body diagrams is essential in solving equilibrium problems
Involves isolating the body of interest
Representing all forces and moments acting on the isolated body
Example: A ladder leaning against a wall can be analyzed using a , showing the forces acting on the ladder (normal force from the wall, normal force from the ground, and the ladder's weight) and the moments they create
Concurrent vs Non-Concurrent Forces
Concurrent Force Systems
Concurrent force systems are those in which all forces act through a single point
For concurrent force systems, the equilibrium equations can be solved by considering the forces acting at the point of concurrency
Example: Multiple cables attached to a single point on a suspended object create a concurrent force system at that attachment point
Non-Concurrent Force Systems
Non-concurrent force systems have forces that do not pass through a single point
Non-concurrent force systems require the consideration of both forces and moments to solve for equilibrium
The moment of a force about a point is the product of the force magnitude and the perpendicular distance from the point to the line of action of the force
states that the moment of a force about a point is equal to the sum of the moments of the force's components about the same point
are a special case of non-concurrent force systems
Consist of two equal and opposite forces with a non-zero moment arm
Produce a pure moment
Example: A beam supported at both ends with a load applied at its midpoint experiences from the supports and the applied load
Equilibrium Applications in Structures
Trusses
Trusses are structural systems composed of connected members, typically forming triangular units
Designed to support loads primarily through axial forces (tension or compression) in the members
The is used to analyze trusses by considering the equilibrium of each joint, assuming pin connections and no moments at the joints
The is an alternative approach to analyzing trusses
Involves the imaginary cut of the truss into two sections
Considers the equilibrium of one of the sections
Example: A bridge truss supporting the weight of vehicles and the bridge deck itself can be analyzed using the method of joints or the method of sections
Frames and Machines
Frames are structures containing multi-force members, which can support loads through axial forces, shear forces, and bending moments
Machines are devices that transmit or modify forces and can be analyzed using equilibrium principles
Consider the forces acting on each component and the connections between them
Example: A crane frame supporting a heavy load can be analyzed by considering the forces acting on each member and the moments they create at the joints
Moment Equilibrium for Rigid Bodies
Moment Equilibrium Principle
is achieved when the sum of all moments acting on a rigid body about any point is zero
The choice of the moment center (the point about which moments are calculated) is arbitrary, but selecting a point that simplifies the calculations is often advantageous
When a rigid body is in equilibrium, the net moment about any point must be zero, regardless of the chosen moment center
Couples and Distributed Loads
The moment of a couple is independent of the choice of the moment center and is always equal to the product of one of the forces and the perpendicular distance between the two forces
In problems involving distributed loads, the concept of the center of gravity or centroid is used to determine the equivalent point load for calculating moments
Example: A rectangular plate subjected to a uniformly distributed load can be analyzed by calculating the moment about a chosen point, considering the total load acting at the plate's centroid