breaks into simpler fractions, making integration and differential equation solving easier. It's a powerful technique that simplifies complex mathematical problems by breaking them down into manageable parts.
This method is crucial for integrating and solving . By decomposing complex fractions, we can tackle problems that would otherwise be too difficult to solve directly, opening up new possibilities in calculus and engineering.
Partial Fraction Decomposition
Concept of partial fraction decomposition
Top images from around the web for Concept of partial fraction decomposition
\begin{align}\frac{7x^{2}-5x+6}{(x-1)(x-3)(x-7)}&=\frac{A}{x-1}+\frac{B}{x-3}+\frac{C}{x-7 ... View original
Is this image relevant?
OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Solving Rational Equations View original
Is this image relevant?
OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Complex Rational Expressions View original
Is this image relevant?
\begin{align}\frac{7x^{2}-5x+6}{(x-1)(x-3)(x-7)}&=\frac{A}{x-1}+\frac{B}{x-3}+\frac{C}{x-7 ... View original
Is this image relevant?
OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Solving Rational Equations View original
Is this image relevant?
1 of 3
Top images from around the web for Concept of partial fraction decomposition
\begin{align}\frac{7x^{2}-5x+6}{(x-1)(x-3)(x-7)}&=\frac{A}{x-1}+\frac{B}{x-3}+\frac{C}{x-7 ... View original
Is this image relevant?
OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Solving Rational Equations View original
Is this image relevant?
OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Complex Rational Expressions View original
Is this image relevant?
\begin{align}\frac{7x^{2}-5x+6}{(x-1)(x-3)(x-7)}&=\frac{A}{x-1}+\frac{B}{x-3}+\frac{C}{x-7 ... View original
Is this image relevant?
OpenAlgebra.com: Free Algebra Study Guide & Video Tutorials: Solving Rational Equations View original
Is this image relevant?
1 of 3
Breaks down complex rational functions into simpler fractions called
Each partial fraction has a denominator that factors the original denominator
Based on the idea that rational functions can be written as sums of partial fractions with linear or
Involves finding of partial fractions
Coefficients determined by solving linear equations or using
Decomposition of rational functions
have numerators with lower degrees than denominators
Decomposition consists only of partial fractions sum
have numerators with degrees greater than or equal to denominators
Decomposition has and proper rational part
Polynomial part obtained by of numerator by denominator
Proper rational part decomposed into partial fractions
:
Factor denominator into distinct linear or irreducible quadratic factors
Set up partial fraction decomposition with for each denominator factor
Multiply equation by original denominator to clear fractions
Equate coefficients of like terms to form
Solve equations system to find unknown coefficients values
Integration using partial fractions
Simplifies
Integration steps:
Perform partial fraction decomposition on rational function
Integrate each partial fraction separately
use : ∫ax+b1dx=a1ln∣ax+b∣+C
Irreducible quadratic denominators use : ∫ax2+bx+c1dx=4ac−b21arctan(4ac−b22ax+b)+C
Add individual integral results for final answer
Differential equations with partial fractions
Solves linear differential equations with
Useful when right-hand side is rational function
Solution steps:
Take of differential equation sides
Isolate transformed dependent variable on one equation side
Perform partial fraction decomposition on resulting rational function
Find of each partial fraction
Add inverse Laplace transform results for general differential equation solution
Apply initial or boundary conditions for particular solution