12.2 Clapeyron equation

The Clapeyron equation is a powerful tool in thermodynamics, linking vapor pressure, temperature, and phase transitions. It's derived from the equilibrium condition between two phases and helps predict how substances behave during vaporization or condensation.

Understanding the Clapeyron equation is crucial for grasping phase equilibria and property relations. It allows us to calculate vapor pressures, predict boiling points at different pressures, and even construct phase diagrams, making it a fundamental concept in thermodynamics.

Clapeyron Equation and Assumptions

Equation and Equilibrium Condition

Top images from around the web for Equation and Equilibrium Condition

• 

  Phase Diagrams | Boundless Chemistry View original

  Is this image relevant?

• 

  Clausius-Clapeyron relation - Knowino View original

  Is this image relevant?

• 

  Clausius-Clapeyron relation - Knowino View original

  Is this image relevant?

• 

  Phase Diagrams | Boundless Chemistry View original

  Is this image relevant?

• 

  Clausius-Clapeyron relation - Knowino View original

  Is this image relevant?

1 of 3

Top images from around the web for Equation and Equilibrium Condition

• 

  Phase Diagrams | Boundless Chemistry View original

  Is this image relevant?

• 

  Clausius-Clapeyron relation - Knowino View original

  Is this image relevant?

• 

  Clausius-Clapeyron relation - Knowino View original

  Is this image relevant?

• 

  Phase Diagrams | Boundless Chemistry View original

  Is this image relevant?

• 

  Clausius-Clapeyron relation - Knowino View original

  Is this image relevant?

1 of 3

• The Clapeyron equation is $[dP/dT](https://www.fiveableKeyTerm:dp/dt) = ΔH_vap/(T ΔV_vap)$, where $dP/dT$ is the slope of the vapor pressure curve, $ΔH_vap$ is the enthalpy of vaporization, $T$ is the absolute temperature, and $ΔV_vap$ is the change in volume upon vaporization
• The Clapeyron equation is derived from the condition of thermodynamic equilibrium between two phases, which requires that the chemical potentials of the two phases are equal at the phase transition temperature and pressure

Assumptions

• The Clapeyron equation assumes that the vapor phase behaves as an ideal gas
• It assumes the molar volume of the liquid phase is negligible compared to the vapor phase
• The enthalpy of vaporization is assumed to be constant over the temperature range of interest

Differential Equation

• The Clapeyron equation is a differential equation that relates the slope of the phase transition line ($dP/dT$) to the thermodynamic properties of the system ($ΔH_vap$, $T$, and $ΔV_vap$)
  • It describes how the vapor pressure changes with temperature along the phase transition line
  • The equation can be used to predict the behavior of a system undergoing a phase transition, such as vaporization or condensation

Slope of Phase Transition Lines

Calculating the Slope

• To calculate the slope of a phase transition line using the Clapeyron equation, one needs to know the enthalpy of vaporization ($ΔH_vap$), the absolute temperature ($T$), and the change in volume upon vaporization ($ΔV_vap$) at the phase transition point
• The change in volume upon vaporization ($ΔV_vap$) can be calculated using the ideal gas law, $ΔV_vap = RT/P$, where $R$ is the universal gas constant, $T$ is the absolute temperature, and $P$ is the pressure at the phase transition point
• The enthalpy of vaporization ($ΔH_vap$) can be determined experimentally using calorimetry or estimated using empirical correlations or group contribution methods

Substituting Values

• Once the values of $ΔH_vap$, $T$, and $ΔV_vap$ are known, the slope of the phase transition line ($dP/dT$) can be calculated by substituting these values into the Clapeyron equation
  • For example, if $ΔH_vap = 40 kJ/mol$, $T = 373 K$, and $ΔV_vap = 30 L/mol$, the slope of the phase transition line would be: $dP/dT = (40 kJ/mol) / (373 K × 30 L/mol) = 3.58 × 10^{-3} bar/K$
  • This positive slope indicates that the vapor pressure increases with increasing temperature along the phase transition line

Clapeyron Equation Terms

Slope of the Vapor Pressure Curve ($dP/dT$)

• The slope of the vapor pressure curve ($dP/dT$) represents the change in vapor pressure with respect to temperature along the phase transition line
• A positive slope indicates that the vapor pressure increases with increasing temperature, while a negative slope indicates that the vapor pressure decreases with increasing temperature
  • Most substances have a positive $dP/dT$ slope because the vapor pressure increases with temperature (water, ethanol)
  • Some substances, such as helium, have a negative $dP/dT$ slope at low temperatures due to quantum mechanical effects

Enthalpy of Vaporization ($ΔH_vap$)

• The enthalpy of vaporization ($ΔH_vap$) represents the amount of heat required to vaporize one mole of the substance at the phase transition temperature and pressure
• A larger $ΔH_vap$ indicates a stronger intermolecular attraction in the liquid phase and a higher boiling point
  • Water has a relatively high $ΔH_vap$ (40.7 kJ/mol at 100°C) due to strong hydrogen bonding, resulting in a high boiling point (100°C at 1 atm)
  • Ethanol has a lower $ΔH_vap$ (38.6 kJ/mol at 78.4°C) and a lower boiling point (78.4°C at 1 atm) compared to water

Absolute Temperature ($T$)

• The absolute temperature ($T$) affects the slope of the phase transition line through its presence in the denominator of the Clapeyron equation
• At higher temperatures, the slope of the phase transition line decreases, indicating a smaller change in vapor pressure with respect to temperature
  • For water, the $dP/dT$ slope decreases from 3.58 × 10^{-3} bar/K at 373 K (100°C) to 1.47 × 10^{-3} bar/K at 473 K (200°C), assuming a constant $ΔH_vap$
  • This means that the vapor pressure of water increases more rapidly with temperature at lower temperatures compared to higher temperatures

Change in Volume upon Vaporization ($ΔV_vap$)

• The change in volume upon vaporization ($ΔV_vap$) represents the difference between the molar volumes of the vapor and liquid phases
• A larger $ΔV_vap$ indicates a greater expansion of the substance upon vaporization and a steeper slope of the phase transition line
  • For water at 100°C and 1 atm, the molar volume of the liquid is 0.018 L/mol, while the molar volume of the vapor is 30.2 L/mol, resulting in a $ΔV_vap$ of 30.2 L/mol
  • Substances with a larger $ΔV_vap$, such as hydrocarbons (pentane, $ΔV_vap$ ≈ 115 L/mol at 25°C), have a steeper $dP/dT$ slope compared to substances with a smaller $ΔV_vap$, such as water

Phase Equilibria Applications

Vapor Pressure Calculations

• The Clapeyron equation can be used to calculate the vapor pressure of a substance at a given temperature, provided that the vapor pressure is known at another temperature and the enthalpy of vaporization is constant over the temperature range
• The Clapeyron equation can be integrated to obtain the Clausius-Clapeyron equation, $ln(P2/P1) = -ΔH_vap/R * (1/T2 - 1/T1)$, which relates the vapor pressures ($P1$ and $P2$) at two different temperatures ($T1$ and $T2$) to the enthalpy of vaporization ($ΔH_vap$) and the universal gas constant ($R$)
  • For example, if the vapor pressure of water is 1 atm at 100°C and the $ΔH_vap$ is 40.7 kJ/mol, the vapor pressure at 90°C can be calculated using the Clausius-Clapeyron equation: $ln(P2/1 atm) = -(40.7 kJ/mol)/(8.314 J/mol·K) * (1/(363 K) - 1/(373 K))$, yielding $P2 = 0.70$ atm

Boiling Point Prediction

• The Clapeyron equation can be used to predict the boiling point of a substance at different pressures, by setting the vapor pressure equal to the desired pressure and solving for the corresponding temperature
  • For example, to find the boiling point of water at 0.5 atm, set $P2 = 0.5$ atm and solve for $T2$ using the Clausius-Clapeyron equation: $ln(0.5 atm/1 atm) = -(40.7 kJ/mol)/(8.314 J/mol·K) * (1/T2 - 1/(373 K))$, yielding $T2 = 354$ K or 81°C
  • This means that water will boil at 81°C when the pressure is reduced to 0.5 atm, which is useful for understanding the behavior of water at high altitudes where the atmospheric pressure is lower

Other Phase Transitions

• The Clapeyron equation can be applied to other phase transitions, such as solid-liquid (melting) and solid-vapor (sublimation), by using the appropriate values of the enthalpy and volume changes for the specific phase transition
  • For the melting of ice at 0°C and 1 atm, $ΔH_fus = 6.01$ kJ/mol and $ΔV_fus = 1.64 × 10^{-5}$ m³/mol, resulting in a $dP/dT$ slope of 134 atm/K
  • This steep slope indicates that a large change in pressure is required to change the melting point of ice by a small amount, which is why ice melts at approximately 0°C over a wide range of pressures

Phase Diagrams

• The Clapeyron equation can be used to construct phase diagrams, which graphically represent the conditions of temperature and pressure at which different phases of a substance coexist in thermodynamic equilibrium
  • The phase diagram of water shows the solid (ice), liquid (water), and vapor (steam) regions, separated by the phase transition lines (melting, vaporization, and sublimation curves)
  • The triple point of water (0.01°C and 0.006 atm) is the point at which all three phases coexist in equilibrium, and the critical point (374°C and 218 atm) is the point above which the liquid and vapor phases become indistinguishable