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15.1 Galois connections and Galois theory

3 min readjuly 23, 2024

Galois connections link two through , establishing a correspondence between their elements. This powerful concept finds applications in various mathematical fields, from algebra to topology, allowing for the transfer of properties between different structures.

In Galois theory, these connections relate field extensions to subgroups of the . This relationship forms the foundation for the , providing a deep insight into the structure of field extensions and their .

Galois Connections and Galois Theory

Definition of Galois connections

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  • Pair of monotone functions between two partially ordered sets establishes correspondence between their elements
    • Given partially ordered sets (A,)(A, \leq) and (B,)(B, \leq), consists of two monotone functions f:ABf: A \to B and g:BAg: B \to A
    • For all aAa \in A and bBb \in B, f(a)b    ag(b)f(a) \leq b \iff a \leq g(b) holds
  • Relates elements of one partially ordered set to elements of another
    • Allows transfer of properties and structures between the two sets (, algebras)
    • Can establish isomorphisms between certain subsets of the partially ordered sets (closure operators, )

Applications in Galois theory

  • Relates field extensions and subgroups of the Galois group
    • Given field extension L/KL/K, Galois group Gal(L/K)\text{Gal}(L/K) is group of of LL that fix KK (symmetries, permutations)
  • Galois connection between partially ordered sets of of LL containing KK and subgroups of Gal(L/K)\text{Gal}(L/K)
    • Monotone functions:
      • f:Subfields(L/K)Subgroups(Gal(L/K))f: \text{Subfields}(L/K) \to \text{Subgroups}(\text{Gal}(L/K)), f(E)={σGal(L/K):σ(x)=x,xE}f(E) = \{\sigma \in \text{Gal}(L/K) : \sigma(x) = x, \forall x \in E\} ()
      • g:Subgroups(Gal(L/K))Subfields(L/K)g: \text{Subgroups}(\text{Gal}(L/K)) \to \text{Subfields}(L/K), g(H)={xL:σ(x)=x,σH}g(H) = \{x \in L : \sigma(x) = x, \forall \sigma \in H\} ()
  • Establishes one-to-one correspondence between subfields of LL containing KK and subgroups of Gal(L/K)\text{Gal}(L/K) (, )

Fundamental theorem proof

  • Using language of category theory:
    • For Galois extension L/KL/K with Galois group GG, between category of intermediate fields of L/KL/K and category of GG-sets
  • Proof relies on Galois connection between subfields of LL containing KK and subgroups of GG
    • from intermediate fields to GG-sets sends subfield EE to set G/HG/H, where H={σG:σ(x)=x,xE}H = \{\sigma \in G : \sigma(x) = x, \forall x \in E\} (cosets, orbits)
    • Functor from GG-sets to intermediate fields sends GG-set XX to field LGxL^{G_x}, where Gx={σG:σ(x)=x}G_x = \{\sigma \in G : \sigma(x) = x\} is stabilizer of element xXx \in X (fixed points)
  • between the two functors constructed using Galois connection prove equivalence of categories (, )

Examples in algebra and geometry

  • Galois connections appear in various algebraic and geometric contexts:
    • Between subgroups of a group and subsets of group closed under conjugation (normal subgroups, )
    • Between submodules of a module and subsets of endomorphism ring (, )
    • Between subspaces of vector space and subspaces of its dual space (, annihilators)
    • Between closed subsets of topological space and ideals of its ring of continuous functions (, )
  • Example in group theory:
    • In group GG, Galois connection between subgroups of GG and subsets of GG closed under conjugation
    • Monotone functions:
      1. f:Subgroups(G)ConjugationClosedSubsets(G)f: \text{Subgroups}(G) \to \text{ConjugationClosedSubsets}(G), f(H)=gGgHg1f(H) = \bigcup_{g \in G} gHg^{-1} ()
      2. g:ConjugationClosedSubsets(G)Subgroups(G)g: \text{ConjugationClosedSubsets}(G) \to \text{Subgroups}(G), g(S)g(S) is subgroup generated by SS ()
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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