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The are key to understanding complex . They give us a way to check if a function is analytic, which is super important in complex analysis. These equations link the real and imaginary parts of a complex function.

By using these equations, we can figure out if a function is analytic and find harmonic conjugates. This helps us solve all sorts of problems in math and physics, like fluid dynamics and electrostatics. It's a powerful tool for working with complex functions.

Cauchy-Riemann Equations

Cartesian and Polar Forms

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  • The Cauchy-Riemann equations provide a necessary and sufficient condition for a complex function to be complex differentiable (analytic) at a point
  • In Cartesian form, for a complex function f(z)=[u(x,y)](https://www.fiveableKeyTerm:u(x,y))+iv(x,y)f(z) = [u(x, y)](https://www.fiveableKeyTerm:u(x,_y)) + iv(x, y), the Cauchy-Riemann equations are:
    • ux=vy\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}
    • uy=vx\frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}
  • In polar form, for a complex function f(z)=u(r,θ)+iv(r,θ)f(z) = u(r, \theta) + iv(r, \theta), the Cauchy-Riemann equations are:
    • ur=1rvθ\frac{\partial u}{\partial r} = \frac{1}{r}\frac{\partial v}{\partial \theta}
    • vr=1ruθ\frac{\partial v}{\partial r} = -\frac{1}{r}\frac{\partial u}{\partial \theta}
  • The Cauchy-Riemann equations relate the partial derivatives of the real and imaginary parts of a complex function

Derivation from Differentiability

  • A complex function f(z)=u(x,y)+iv(x,y)f(z) = u(x, y) + iv(x, y) is differentiable at a point z0z_0 if the limit of f(z)f(z0)zz0\frac{f(z) - f(z_0)}{z - z_0} exists as zz approaches z0z_0, independent of the path along which zz approaches z0z_0
  • Applying the limit definition of the derivative to the real and imaginary parts of f(z)f(z) separately leads to the Cauchy-Riemann equations
  • The derivation involves considering the limit along the real and imaginary axes and equating the corresponding components, resulting in the partial derivative relations
  • The derivation can also be performed using the polar form of the complex function, leading to the polar form of the Cauchy-Riemann equations
  • The existence of the complex derivative implies the existence and continuity of the partial derivatives satisfying the Cauchy-Riemann equations

Differentiability and Cauchy-Riemann Equations

Analyticity and Differentiability

  • A complex function is analytic (complex differentiable) at a point if it is differentiable in a neighborhood of that point
  • For a complex function to be analytic at a point or in a region, the Cauchy-Riemann equations must be satisfied at that point or throughout the region
  • If the Cauchy-Riemann equations are satisfied and the partial derivatives are continuous at a point, then the function is analytic at that point
  • If the Cauchy-Riemann equations are satisfied throughout a region and the partial derivatives are continuous in that region, then the function is analytic in that region
  • Analyticity is a stronger condition than differentiability, as it requires the function to be differentiable in a neighborhood of a point

Checking Analyticity

  • To determine if a complex function is analytic, compute the partial derivatives of the real and imaginary parts and check them against the Cauchy-Riemann equations
  • Example: For f(z)=z2=(x+iy)2=(x2y2)+i(2xy)f(z) = z^2 = (x + iy)^2 = (x^2 - y^2) + i(2xy), we have:
    • u(x,y)=x2y2u(x, y) = x^2 - y^2, [v(x,y)](https://www.fiveableKeyTerm:v(x,y))=2xy[v(x, y)](https://www.fiveableKeyTerm:v(x,_y)) = 2xy
    • ux=2x\frac{\partial u}{\partial x} = 2x, vy=2x\frac{\partial v}{\partial y} = 2x
    • uy=2y\frac{\partial u}{\partial y} = -2y, vx=2y\frac{\partial v}{\partial x} = 2y
    • The Cauchy-Riemann equations are satisfied, and the partial derivatives are continuous everywhere, so f(z)=z2f(z) = z^2 is analytic in the entire complex plane
  • Example: For f(z)=zˉ=xiyf(z) = \bar{z} = x - iy, we have:
    • u(x,y)=xu(x, y) = x, v(x,y)=yv(x, y) = -y
    • ux=1\frac{\partial u}{\partial x} = 1, vy=1\frac{\partial v}{\partial y} = -1
    • uy=0\frac{\partial u}{\partial y} = 0, vx=0\frac{\partial v}{\partial x} = 0
    • The Cauchy-Riemann equations are not satisfied, so f(z)=zˉf(z) = \bar{z} is not analytic anywhere

Analyticity Using Cauchy-Riemann Equations

Harmonic Functions and Conjugates

  • A real-valued function u(x,y)u(x, y) is called harmonic if it satisfies Laplace's equation: 2ux2+2uy2=0\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0
  • If u(x,y)u(x, y) is a harmonic function, then there exists a harmonic conjugate v(x,y)v(x, y) such that f(z)=u(x,y)+iv(x,y)f(z) = u(x, y) + iv(x, y) is analytic
  • The harmonic conjugate can be found by integrating the Cauchy-Riemann equations:
    • v(x,y)=uxdy+C(x)v(x, y) = \int \frac{\partial u}{\partial x} dy + C(x) or v(x,y)=uydx+C(y)v(x, y) = -\int \frac{\partial u}{\partial y} dx + C(y)
  • Example: If u(x,y)=excosyu(x, y) = e^x \cos y, then v(x,y)=exsinyv(x, y) = e^x \sin y is its harmonic conjugate, and f(z)=excosy+iexsiny=ezf(z) = e^x \cos y + i e^x \sin y = e^z is analytic

Laplace's Equation

  • The Cauchy-Riemann equations can be used to derive Laplace's equation in two dimensions
  • If f(z)=u(x,y)+iv(x,y)f(z) = u(x, y) + iv(x, y) is analytic, then both u(x,y)u(x, y) and v(x,y)v(x, y) satisfy Laplace's equation:
    • 2ux2+2uy2=0\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 and 2vx2+2vy2=0\frac{\partial^2 v}{\partial x^2} + \frac{\partial^2 v}{\partial y^2} = 0
  • This property is useful in solving boundary value problems in various fields, such as fluid dynamics and electrostatics
  • Example: In electrostatics, the electric potential ϕ(x,y)\phi(x, y) satisfies Laplace's equation in charge-free regions, and the electric field components can be found using the Cauchy-Riemann equations:
    • Ex=ϕxE_x = -\frac{\partial \phi}{\partial x} and Ey=ϕyE_y = -\frac{\partial \phi}{\partial y}

Applications of Cauchy-Riemann Equations

Analytic Function Properties

  • The Cauchy-Riemann equations can be used to prove properties of analytic functions, such as the Cauchy-Riemann theorem and the Cauchy integral formula
  • Cauchy-Riemann Theorem: If f(z)f(z) is analytic in a simply connected domain DD and CC is a simple closed curve in DD, then Cf(z)dz=0\oint_C f(z) dz = 0
  • Cauchy Integral Formula: If f(z)f(z) is analytic in a simply connected domain DD and CC is a simple closed curve in DD enclosing a point z0z_0, then f(z0)=12πiCf(z)zz0dzf(z_0) = \frac{1}{2\pi i} \oint_C \frac{f(z)}{z - z_0} dz
  • These theorems are fundamental in complex analysis and have numerous applications in mathematics and physics

Boundary Value Problems

  • The Cauchy-Riemann equations can be used to solve boundary value problems in various fields, such as fluid dynamics, electrostatics, and heat transfer
  • In these problems, the solution is often a complex function whose real and imaginary parts satisfy certain boundary conditions
  • Example: In fluid dynamics, the complex potential W(z)=ϕ(x,y)+iψ(x,y)W(z) = \phi(x, y) + i\psi(x, y) is used to describe the flow of an ideal fluid, where ϕ(x,y)\phi(x, y) is the velocity potential and ψ(x,y)\psi(x, y) is the stream function
    • The Cauchy-Riemann equations relate the velocity components to the potential and stream functions: ux=ϕx=ψyu_x = \frac{\partial \phi}{\partial x} = \frac{\partial \psi}{\partial y} and uy=ϕy=ψxu_y = \frac{\partial \phi}{\partial y} = -\frac{\partial \psi}{\partial x}
    • Boundary conditions on the velocity components or the stream function can be used to determine the complex potential and solve for the flow field
  • Example: In electrostatics, the complex potential W(z)=ϕ(x,y)+iψ(x,y)W(z) = \phi(x, y) + i\psi(x, y) is used to describe the electric field in two dimensions, where ϕ(x,y)\phi(x, y) is the electric potential and ψ(x,y)\psi(x, y) is the electric flux function
    • The Cauchy-Riemann equations relate the electric field components to the potential and flux functions: Ex=ϕx=ψyE_x = -\frac{\partial \phi}{\partial x} = \frac{\partial \psi}{\partial y} and Ey=ϕy=ψxE_y = -\frac{\partial \phi}{\partial y} = -\frac{\partial \psi}{\partial x}
    • Boundary conditions on the electric potential or the flux function can be used to determine the complex potential and solve for the electric field
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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