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Second-order linear ODEs are key in mathematical physics. They model everything from to complex wave phenomena. Understanding their classification and solutions is crucial for tackling real-world problems.

This section covers how to classify these ODEs, find general solutions for homogeneous cases, and handle non-homogeneous equations. We'll also look at initial value problems and apply these concepts to physical systems like oscillators.

Classification and General Solutions of Second-Order Linear ODEs

Classification of second-order linear ODEs

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  • General form of a second-order linear ODE with constant coefficients is ay+by+cy=f(x)ay'' + by' + cy = f(x) where aa, bb, and cc are constants with a0a \neq 0 and f(x)f(x) is a function of xx
  • Homogeneous ODEs have f(x)=0f(x) = 0 while non-homogeneous ODEs have f(x)0f(x) \neq 0
  • ar2+br+c=0ar^2 + br + c = 0 determines the type of solution based on its roots
    • Real and distinct roots lead to a solution of the form y=c1er1x+c2er2xy = c_1e^{r_1x} + c_2e^{r_2x} (r1r2r_1 \neq r_2)
    • Real and repeated roots result in a solution of the form y=(c1+c2x)erxy = (c_1 + c_2x)e^{rx}
    • Complex conjugate roots α±iβ\alpha \pm i\beta give a solution of the form y=eαx(c1cos(βx)+c2sin(βx))y = e^{\alpha x}(c_1\cos(\beta x) + c_2\sin(\beta x))

General solutions for homogeneous ODEs

  • Find the roots of the characteristic equation ar2+br+c=0ar^2 + br + c = 0
  • Construct the based on the type of roots obtained
    • For real and distinct roots r1r_1 and r2r_2, the solution is y=c1er1x+c2er2xy = c_1e^{r_1x} + c_2e^{r_2x}
    • For real and repeated roots rr, the solution is y=(c1+c2x)erxy = (c_1 + c_2x)e^{rx}
    • For complex conjugate roots α±iβ\alpha \pm i\beta, the solution is y=eαx(c1cos(βx)+c2sin(βx))y = e^{\alpha x}(c_1\cos(\beta x) + c_2\sin(\beta x)) where α\alpha and β\beta are the real and imaginary parts of the roots

Particular solutions for non-homogeneous ODEs

  • Use the method of to find particular solutions of non-homogeneous ODEs
  • Identify the form of the based on the non-homogeneous term f(x)f(x)
    1. For polynomial f(x)f(x) of degree nn, use yp=Anxn+An1xn1++A1x+A0y_p = A_nx^n + A_{n-1}x^{n-1} + \cdots + A_1x + A_0
    2. For exponential f(x)=eαxf(x) = e^{\alpha x}, use yp=Aeαxy_p = Ae^{\alpha x}
    3. For trigonometric f(x)=cos(βx)f(x) = \cos(\beta x) or sin(βx)\sin(\beta x), use yp=Acos(βx)+Bsin(βx)y_p = A\cos(\beta x) + B\sin(\beta x)
  • Substitute the particular solution into the ODE and solve for the unknown coefficients (An,An1,,A1,A0,A,BA_n, A_{n-1}, \ldots, A_1, A_0, A, B)
  • The general solution is the sum of the homogeneous solution yhy_h and the particular solution ypy_p, i.e., y=yh+ypy = y_h + y_p

Initial value problems in ODEs

  • Determine the general solution by finding both the homogeneous and particular solutions
  • Apply the given to find the values of arbitrary constants c1c_1 and c2c_2
    1. Substitute the initial conditions into the general solution and its first derivative
    2. Solve the resulting system of equations for the arbitrary constants

Applications of ODEs in physics

  • Model simple harmonic oscillators using the ODE my+ky=0my'' + ky = 0 where mm is the mass and kk is the spring constant
    • The solution is y=Acos(ωt)+Bsin(ωt)y = A\cos(\omega t) + B\sin(\omega t) with angular frequency ω=km\omega = \sqrt{\frac{k}{m}}
  • Describe damped harmonic oscillators using the ODE my+cy+ky=0my'' + cy' + ky = 0 where cc is the damping coefficient
    • The solution depends on the roots of the characteristic equation
      1. Overdamped (real, distinct, negative roots): y=c1er1t+c2er2ty = c_1e^{r_1t} + c_2e^{r_2t}
      2. Critically damped (real, repeated, negative roots): y=(c1+c2t)ec2mty = (c_1 + c_2t)e^{-\frac{c}{2m}t}
      3. Underdamped (complex conjugate roots): y=ec2mt(c1cos(ωt)+c2sin(ωt))y = e^{-\frac{c}{2m}t}(c_1\cos(\omega t) + c_2\sin(\omega t)) with ω=4mkc24m2\omega = \sqrt{\frac{4mk-c^2}{4m^2}}
  • Analyze forced harmonic oscillators described by the ODE my+cy+ky=F(t)my'' + cy' + ky = F(t) where F(t)F(t) is the external forcing function
    • The solution is the sum of the homogeneous solution and a particular solution depending on the form of F(t)F(t)
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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