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and are key concepts in algebraic geometry. They measure the complexity of algebraic structures and spaces. Understanding these ideas helps us grasp the fundamental properties of rings, varieties, and their relationships.

These concepts connect abstract algebra with geometry. By studying prime ideals and chains, we can determine the dimension of algebraic objects. This knowledge is crucial for analyzing the structure and behavior of algebraic varieties and their coordinate rings.

Krull dimension for rings

Definition and properties

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  • The Krull dimension of a ring RR is the supremum of the lengths of all chains of prime ideals in RR, where the length of a chain is the number of strict inclusions
    • For example, if R=k[x,y]R = k[x, y] and P0P1P2P_0 \subsetneq P_1 \subsetneq P_2 is a chain of prime ideals, then the length of this chain is 2
  • For an integral domain RR, the Krull dimension is equal to the transcendence degree of its field of fractions over its prime subfield
    • For instance, the field of fractions of Q[x,y]\mathbb{Q}[x, y] is Q(x,y)\mathbb{Q}(x, y), which has transcendence degree 2 over Q\mathbb{Q}, so the Krull dimension of Q[x,y]\mathbb{Q}[x, y] is 2
  • The Krull dimension of a is finite, and it coincides with the maximum length of a chain of prime ideals in the ring
    • A ring is noetherian if it satisfies the ascending chain condition on ideals, meaning that any ascending chain of ideals stabilizes (becomes constant) after finitely many steps

Relationship to algebraic varieties

  • The Krull dimension of a finitely generated algebra over a field kk is equal to the dimension of the corresponding algebraic variety defined over kk
    • For example, the polynomial ring k[x,y,z]/(x2+y2z2)k[x, y, z]/(x^2 + y^2 - z^2) corresponds to the V(x2+y2z2)V(x^2 + y^2 - z^2) in A3\mathbb{A}^3, which is a quadric surface of dimension 2
  • For an affine algebraic variety VV, the Krull dimension of its coordinate ring is equal to the dimension of VV as a topological space
    • The coordinate ring of an affine variety VAnV \subseteq \mathbb{A}^n is the quotient ring k[x1,,xn]/I(V)k[x_1, \ldots, x_n]/I(V), where I(V)I(V) is the ideal of polynomials vanishing on VV

Computing Krull dimension

Common rings

  • The Krull dimension of a field is 0, as the only prime ideal is the zero ideal
    • For instance, dimKrull(Q)=0\dim_{\text{Krull}}(\mathbb{Q}) = 0 and dimKrull(C)=0\dim_{\text{Krull}}(\mathbb{C}) = 0
  • The Krull dimension of the polynomial ring k[x1,,xn]k[x_1, \ldots, x_n] over a field kk is nn, as the longest chain of prime ideals corresponds to the chain of irreducible subvarieties
    • For example, dimKrull(R[x,y,z])=3\dim_{\text{Krull}}(\mathbb{R}[x, y, z]) = 3
  • The Krull dimension of the ring of integers Z\mathbb{Z} is 1, as the prime ideals are (0)(0) and (p)(p) for each prime number pp
    • The chain (0)(p)(0) \subsetneq (p) has length 1, and there are no longer chains of prime ideals in Z\mathbb{Z}
  • The Krull dimension of a product of rings R1××RnR_1 \times \cdots \times R_n is the maximum of the Krull dimensions of the individual rings RiR_i
    • For instance, dimKrull(Z×Q[x])=max{1,1}=1\dim_{\text{Krull}}(\mathbb{Z} \times \mathbb{Q}[x]) = \max\{1, 1\} = 1

Affine varieties

  • For an affine variety VV defined by a prime ideal II in k[x1,,xn]k[x_1, \ldots, x_n], the Krull dimension of VV is equal to nht(I)n - \operatorname{ht}(I), where ht(I)\operatorname{ht}(I) is the height of the ideal II
    • The II is the supremum of the lengths of chains of prime ideals contained in II
    • For example, if V=V(xy1)A2V = V(xy - 1) \subseteq \mathbb{A}^2, then I(V)=(xy1)I(V) = (xy - 1) has height 1, so dimKrull(V)=21=1\dim_{\text{Krull}}(V) = 2 - 1 = 1

Krull dimension properties

Localization and quotients

  • For a ring RR and a multiplicative subset SS, the Krull dimension of the localization S1RS^{-1}R is equal to the Krull dimension of RR
    • This follows from the correspondence between prime ideals in RR and prime ideals in S1RS^{-1}R that do not intersect SS
    • For example, dimKrull(Z(p))=dimKrull(Z)=1\dim_{\text{Krull}}(\mathbb{Z}_{(p)}) = \dim_{\text{Krull}}(\mathbb{Z}) = 1, where Z(p)\mathbb{Z}_{(p)} is the localization of Z\mathbb{Z} at the prime ideal (p)(p)
  • For a ring RR and an ideal II, the Krull dimension of the quotient ring R/IR/I is less than or equal to the Krull dimension of RR
    • This inequality becomes an equality if II is a minimal prime ideal
    • For instance, dimKrull(Z/6Z)=0dimKrull(Z)=1\dim_{\text{Krull}}(\mathbb{Z}/6\mathbb{Z}) = 0 \leq \dim_{\text{Krull}}(\mathbb{Z}) = 1

Noetherian integral domains

  • If RR is a finitely generated algebra over a field kk and PP is a prime ideal of RR, then dim(R/P)+ht(P)=dim(R)\dim(R/P) + \operatorname{ht}(P) = \dim(R), where dim\dim denotes the Krull dimension
    • This property relates the dimension of a quotient ring to the height of the corresponding prime ideal
  • For a noetherian integral domain RR, the Krull dimension of RR is equal to the supremum of the heights of maximal ideals in RR
    • A maximal ideal is a proper ideal that is not contained in any other proper ideal

Krull dimension vs transcendence degree

Finitely generated field extensions

  • For a finitely generated K/kK/k, the transcendence degree of KK over kk is equal to the Krull dimension of any finitely generated kk-subalgebra RR of KK such that the field of fractions of RR is KK
    • The transcendence degree of a field extension K/kK/k is the maximum number of algebraically independent elements in KK over kk
    • For example, if K=k(x,y)K = k(x, y) and R=k[x,y]R = k[x, y], then dimKrull(R)=tr.degk(K)=2\dim_{\text{Krull}}(R) = \operatorname{tr.deg}_k(K) = 2

Integral domains and function fields

  • If RR is an integral domain with field of fractions KK, then the Krull dimension of RR is equal to the transcendence degree of KK over the prime subfield of RR
    • The prime subfield of a ring is the smallest subfield contained in the ring (e.g., Q\mathbb{Q} for Z\mathbb{Z} or Q[x]\mathbb{Q}[x])
  • For an affine variety VV over a field kk, the dimension of VV is equal to the transcendence degree of the function field k(V)k(V) over kk
    • The function field k(V)k(V) is the field of rational functions on VV, which consists of quotients of polynomials in the coordinate ring of VV

Polynomial rings and rational function fields

  • The Krull dimension of a finitely generated algebra RR over a field kk is equal to the transcendence degree of the field of fractions of RR over kk
    • For instance, if R=k[x,y,z]/(x2+y2z2)R = k[x, y, z]/(x^2 + y^2 - z^2), then its field of fractions has transcendence degree 2 over kk, so dimKrull(R)=2\dim_{\text{Krull}}(R) = 2
  • The Krull dimension of a polynomial ring k[x1,,xn]k[x_1, \ldots, x_n] is equal to the transcendence degree of the field of rational functions k(x1,,xn)k(x_1, \ldots, x_n) over kk
    • The field of rational functions k(x1,,xn)k(x_1, \ldots, x_n) consists of quotients of polynomials in k[x1,,xn]k[x_1, \ldots, x_n]
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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