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8.6 Parametric Equations

2 min readjune 25, 2024

offer a powerful way to describe curves and motion using a . They allow us to represent complex shapes and trajectories that can't be easily expressed with standard functions. This approach opens up new possibilities for modeling and analysis.

Converting between parametric and rectangular forms is crucial for working with these equations. We can also use calculus techniques to find tangent lines, velocities, and arc lengths. Understanding how the parameter affects curve shape and position is key to mastering this topic.

Parametric Equations

Parametric to rectangular conversion

Top images from around the web for Parametric to rectangular conversion
Top images from around the web for Parametric to rectangular conversion
  • Parametric equations define a curve using two equations x(t)x(t) and y(t)y(t) with parameter tt (circle)
  • Convert parametric to rectangular by eliminating tt
    • Solve one equation for tt and substitute into the other
    • x(t)=t2x(t) = t^2, y(t)=t3y(t) = t^3, solve x(t)x(t) for t=xt = \sqrt{x}, substitute into y(t)y(t) to get y=x3/2y = x^{3/2}
  • Convert rectangular to parametric by introducing tt
    • Express xx and yy as functions of tt
    • y=x2y = x^2, let x(t)=tx(t) = t and y(t)=t2y(t) = t^2

Modeling with parametric equations

  • Model 2D motion with x(t)x(t) and y(t)y(t) representing position at time tt
    • launched with velocity vv at angle θ\theta: x(t)=vcos(θ)tx(t) = v\cos(\theta)t and y(t)=vsin(θ)t12gt2y(t) = v\sin(\theta)t - \frac{1}{2}gt^2, gg is gravity
  • Model shapes and curves
    • (path traced by point on rolling circle): x(t)=r(tsin(t))x(t) = r(t - \sin(t)) and y(t)=r(1cos(t))y(t) = r(1 - \cos(t)), rr is circle radius
  • can represent parametric curves in higher dimensions

Calculus of parametric curves

  • Derivatives provide curve information
    • First derivatives dxdt\frac{dx}{dt} and dydt\frac{dy}{dt} are
    • Second derivatives d2xdt2\frac{d^2x}{dt^2} and d2ydt2\frac{d^2y}{dt^2} are
  • Find slope using first derivatives: dy/dtdx/dt\frac{dy/dt}{dx/dt}
  • Calculate with integrals: ab(dxdt)2+(dydt)2dt\int_{a}^{b} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} dt

Geometric interpretation of parameters

  • Parameter tt represents different quantities based on context
    • Motion problems: tt is often time
    • Shape problems: tt may be angle or proportion
  • Parameter domain determines portion of curve considered
    • Unit circle x(t)=cos(t)x(t) = \cos(t), y(t)=sin(t)y(t) = \sin(t), domain 0t2π0 \leq t \leq 2\pi is one revolution
  • Parameter values affect curve shape and position
    • Cycloid equations x(t)=r(tsin(t))x(t) = r(t - \sin(t)), y(t)=r(1cos(t))y(t) = r(1 - \cos(t)), changing rr changes cycloid size

Advanced parametric representations

  • can be expressed parametrically as x(t)=r(t)cos(t)x(t) = r(t)\cos(t), y(t)=r(t)sin(t)y(t) = r(t)\sin(t)
  • analysis uses parametric equations to study dynamical systems
  • Parametric surfaces extend the concept to three dimensions, defining a surface with three equations x(u,v)x(u,v), y(u,v)y(u,v), and z(u,v)z(u,v)
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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
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