Parametric equations offer a powerful way to describe curves and motion using a parameter . They allow us to represent complex shapes and trajectories that can't be easily expressed with standard functions. This approach opens up new possibilities for modeling and analysis.
Converting between parametric and rectangular forms is crucial for working with these equations. We can also use calculus techniques to find tangent lines, velocities, and arc lengths. Understanding how the parameter affects curve shape and position is key to mastering this topic.
Parametric Equations
Parametric to rectangular conversion
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Parametric equations define a curve using two equations x ( t ) x(t) x ( t ) and y ( t ) y(t) y ( t ) with parameter t t t (circle)
Convert parametric to rectangular by eliminating t t t
Solve one equation for t t t and substitute into the other
x ( t ) = t 2 x(t) = t^2 x ( t ) = t 2 , y ( t ) = t 3 y(t) = t^3 y ( t ) = t 3 , solve x ( t ) x(t) x ( t ) for t = x t = \sqrt{x} t = x , substitute into y ( t ) y(t) y ( t ) to get y = x 3 / 2 y = x^{3/2} y = x 3/2
Convert rectangular to parametric by introducing t t t
Express x x x and y y y as functions of t t t
y = x 2 y = x^2 y = x 2 , let x ( t ) = t x(t) = t x ( t ) = t and y ( t ) = t 2 y(t) = t^2 y ( t ) = t 2
Modeling with parametric equations
Model 2D motion with x ( t ) x(t) x ( t ) and y ( t ) y(t) y ( t ) representing position at time t t t
Projectile launched with velocity v v v at angle θ \theta θ : x ( t ) = v cos ( θ ) t x(t) = v\cos(\theta)t x ( t ) = v cos ( θ ) t and y ( t ) = v sin ( θ ) t − 1 2 g t 2 y(t) = v\sin(\theta)t - \frac{1}{2}gt^2 y ( t ) = v sin ( θ ) t − 2 1 g t 2 , g g g is gravity
Model shapes and curves
Cycloid (path traced by point on rolling circle): x ( t ) = r ( t − sin ( t ) ) x(t) = r(t - \sin(t)) x ( t ) = r ( t − sin ( t )) and y ( t ) = r ( 1 − cos ( t ) ) y(t) = r(1 - \cos(t)) y ( t ) = r ( 1 − cos ( t )) , r r r is circle radius
Vector-valued functions can represent parametric curves in higher dimensions
Calculus of parametric curves
Derivatives provide curve information
First derivatives d x d t \frac{dx}{dt} d t d x and d y d t \frac{dy}{dt} d t d y are velocity components
Second derivatives d 2 x d t 2 \frac{d^2x}{dt^2} d t 2 d 2 x and d 2 y d t 2 \frac{d^2y}{dt^2} d t 2 d 2 y are acceleration components
Find tangent line slope using first derivatives: d y / d t d x / d t \frac{dy/dt}{dx/dt} d x / d t d y / d t
Calculate arc length with integrals: ∫ a b ( d x d t ) 2 + ( d y d t ) 2 d t \int_{a}^{b} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} dt ∫ a b ( d t d x ) 2 + ( d t d y ) 2 d t
Geometric interpretation of parameters
Parameter t t t represents different quantities based on context
Motion problems: t t t is often time
Shape problems: t t t may be angle or proportion
Parameter domain determines portion of curve considered
Unit circle x ( t ) = cos ( t ) x(t) = \cos(t) x ( t ) = cos ( t ) , y ( t ) = sin ( t ) y(t) = \sin(t) y ( t ) = sin ( t ) , domain 0 ≤ t ≤ 2 π 0 \leq t \leq 2\pi 0 ≤ t ≤ 2 π is one revolution
Parameter values affect curve shape and position
Cycloid equations x ( t ) = r ( t − sin ( t ) ) x(t) = r(t - \sin(t)) x ( t ) = r ( t − sin ( t )) , y ( t ) = r ( 1 − cos ( t ) ) y(t) = r(1 - \cos(t)) y ( t ) = r ( 1 − cos ( t )) , changing r r r changes cycloid size
Advanced parametric representations
Polar coordinates can be expressed parametrically as x ( t ) = r ( t ) cos ( t ) x(t) = r(t)\cos(t) x ( t ) = r ( t ) cos ( t ) , y ( t ) = r ( t ) sin ( t ) y(t) = r(t)\sin(t) y ( t ) = r ( t ) sin ( t )
Phase plane analysis uses parametric equations to study dynamical systems
Parametric surfaces extend the concept to three dimensions, defining a surface with three equations x ( u , v ) x(u,v) x ( u , v ) , y ( u , v ) y(u,v) y ( u , v ) , and z ( u , v ) z(u,v) z ( u , v )