Indefinite integration techniques are essential tools for solving complex integrals. These methods, including , , , and trigonometric strategies, help simplify and break down challenging integrals into manageable parts.
By mastering these techniques, you'll be able to tackle a wide range of integration problems. Each method has its strengths, and knowing when to apply them is key to becoming proficient in calculus and mathematical problem-solving.
Indefinite Integration Techniques
Substitution for indefinite integrals
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Unit 2: Rules for integration – National Curriculum (Vocational) Mathematics Level 4 View original
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Introduces a new variable (often u) as a function of the original variable x to simplify complex integrals
Substitution u=g(x) chosen to simplify the integrand
Differential du expressed in terms of [dx](https://www.fiveableKeyTerm:dx) using the chain rule: du=g′(x)dx
Steps to apply substitution:
Identify a suitable substitution u=g(x) that simplifies the integrand
Express the integrand in terms of u and du
Integrate the simplified expression with respect to u
Substitute back the original variable x to obtain the final result
Examples of integrals solvable using substitution:
∫xx2+1dx (let u=x2+1)
∫e2xcos(ex)dx (let u=ex)
Integration by parts technique
Used to integrate products of functions based on the product rule for derivatives
Formula for integration by parts: ∫udv=uv−∫vdu
Steps to apply integration by parts:
Identify functions u and dv in the integrand
u chosen as a function that becomes simpler when differentiated
dv chosen such that it can be easily integrated
Compute du by differentiating u and v by integrating dv
Apply the integration by parts formula: ∫udv=uv−∫vdu
Repeat the process if necessary until the integral becomes simpler to evaluate
Examples of integrals solvable using integration by parts:
∫xsin(x)dx (let u=x and dv=sin(x)dx)
∫ln(x)dx (let u=ln(x) and dv=dx)
Partial fractions in integration
Used to integrate (quotients of polynomials) by expressing them as a sum of simpler fractions
Steps to apply partial fraction decomposition:
Factor the denominator of the rational function into irreducible factors
Set up a decomposition with unknown coefficients for each factor in the denominator
Linear factors (x−a) use the form x−aA
Repeated linear factors (x−a)n use the form x−aA1+(x−a)2A2+⋯+(x−a)nAn
Irreducible quadratic factors (ax2+bx+c) use the form ax2+bx+cBx+C
Solve for the unknown coefficients by equating the decomposition to the original rational function and comparing coefficients or evaluating at specific points
Integrate each resulting fraction separately using known integration techniques
Examples of rational functions integrable using partial fraction decomposition:
∫x2−42x+1dx
∫(x−1)(x+2)23x−2dx
Strategies for trigonometric integrals
Techniques for integrating functions containing sine, cosine, tangent, or their reciprocals:
Basic :
∫sin(x)dx=−cos(x)+C
∫cos(x)dx=sin(x)+C
∫sec2(x)dx=tan(x)+C
∫csc2(x)dx=−cot(x)+C
Trigonometric substitution used when the integrand contains a2−x2, a2+x2, or x2−a2
Substitute x=asin(θ), x=atan(θ), or x=asec(θ), respectively
Simplify the integrand and integrate with respect to θ
Substitute back the original variable x
Integration by parts applied when the integrand is a product of trigonometric and algebraic functions (example: ∫xcos(x)dx)
used to simplify the integrand before integrating (examples: sin2(x)=21−cos(2x), cos2(x)=21+cos(2x))